Sql 计算通过联接表返回的不同项数

我有3个表，

用户、付款、付款类型

比如：

当加入表格来查询我得到的男人的报酬时

userID  userName    namePayment     info
1       Tom         Cash            ball
1       Tom         Cash            book
1       Tom         Check           book
2       Kate        Cash            book

通过以下查询

SELECT u.userID ,u.userName, te.namePayment , e.info
FROM User u
  INNER JOIN Payment e 
     ON u.userID = e.idUser     
  INNER JOIN typePayment te 
     ON e.idTypePayment = te.typeID
 order by u.userID;

但是，我想计算一下向每个人支付的总类型的数量，如：

userID  userName    namePayment     info    noCash  noCheck  noBoth
1       Tom         Cash            ball        2         1       0
1       Tom         Cash            book        2         1       0
1       Tom         Check           book        2         1       0
2       Kate        Cash            book        1         0       0

---

怎么做？（请看一看，我正在使用SQLite）

为什么您希望一个用户有多行？而且，

noBoth

没有意义

此查询获取每个用户的不同付款类型：

SELECT u.userID, u.userName,
       SUM(CASE WHEN te.namePayment = 'Cash' THEN 1 ELSE 0 END) as NumCash,           
       SUM(CASE WHEN te.namePayment = 'Check' THEN 1 ELSE 0 END) as NumCheck,
       SUM(CASE WHEN te.namePayment IN ('Cash', 'Check' ) THEN 1 ELSE 0 END) as NumBoth
FROM User u INNER JOIN
     Payment e 
     ON u.userID = e.idUser INNER JOIN
     typePayment te 
     ON e.idTypePayment = te.typeID
GROUP BY u.userID;
ORDER BY u.userID;

---

如果您愿意，您可以将其加入到更详细的信息中，以添加每笔付款的列。

为什么您希望一个用户有多行？而且，

noBoth

没有意义

此查询获取每个用户的不同付款类型：

SELECT u.userID, u.userName,
       SUM(CASE WHEN te.namePayment = 'Cash' THEN 1 ELSE 0 END) as NumCash,           
       SUM(CASE WHEN te.namePayment = 'Check' THEN 1 ELSE 0 END) as NumCheck,
       SUM(CASE WHEN te.namePayment IN ('Cash', 'Check' ) THEN 1 ELSE 0 END) as NumBoth
FROM User u INNER JOIN
     Payment e 
     ON u.userID = e.idUser INNER JOIN
     typePayment te 
     ON e.idTypePayment = te.typeID
GROUP BY u.userID;
ORDER BY u.userID;

---

如果你真的喜欢，你可以将其加入到更详细的信息中，以添加每笔付款的列。

noBoth

是拥有

Cash

和

Check

的总和。noBoth是拥有

Cash

和

Check