SQL-根据列中的值之和获取一对行

我的桌子看起来像这样：

+------+------+-------+------+
| ColA | ColB | ColC  | ColD |
+------+------+-------+------+
| 1    | 1    | 10217 | 5    |
+------+------+-------+------+
| 1    | 2    | 10217 | 6    |
+------+------+-------+------+
| 1    | 1    | 10417 | 7    |
+------+------+-------+------+
| 1    | 2    | 10417 | 8    |
+------+------+-------+------+
| 2    | 1    | 10417 | 9    |
+------+------+-------+------+
| 2    | 2    | 10417 | 10   |
+------+------+-------+------+

如何编写一个查询，返回一对具有以下要求的行：

输入ColA值和ColC范围作为参数后

e、 可乐：1可乐：10217至10417

该表应如下所示：

+------+------+-------+------+
| ColA | ColB | ColC  | ColD |
+------+------+-------+------+
| 1    | 1    | 10217 | 5    |
+------+------+-------+------+
| 1    | 2    | 10217 | 6    |
+------+------+-------+------+
| 1    | 1    | 10417 | 7    |
+------+------+-------+------+
| 1    | 2    | 10417 | 8    |
+------+------+-------+------+

+------+------+-------+------+
| ColA | ColB | ColC  | ColD |
+------+------+-------+------+
| 1    | 1    | 10417 | 7    |
+------+------+-------+------+
| 1    | 2    | 10417 | 8    |
+------+------+-------+------+

现在为特定ColC值的每个ColB对添加ColD值。使用我的示例，对于ColC值10217，它将是5+6，ColC值10417将是7+8。 然后得到两个和之间的最大值。所以它将是15>11。 最后，返回获得上面的最大值（15）所产生的行对。 最终结果应如下所示：

+------+------+-------+------+
| ColA | ColB | ColC  | ColD |
+------+------+-------+------+
| 1    | 1    | 10217 | 5    |
+------+------+-------+------+
| 1    | 2    | 10217 | 6    |
+------+------+-------+------+
| 1    | 1    | 10417 | 7    |
+------+------+-------+------+
| 1    | 2    | 10417 | 8    |
+------+------+-------+------+

+------+------+-------+------+
| ColA | ColB | ColC  | ColD |
+------+------+-------+------+
| 1    | 1    | 10417 | 7    |
+------+------+-------+------+
| 1    | 2    | 10417 | 8    |
+------+------+-------+------+

我只得到了最大值的部分。我在尝试获得行配对时遇到了困难

SELECT Max(sumD) AS maxSumD
FROM (SELECT t1.ColA, t1.ColB, sum(ColD) AS sumD 
        FROM (SELECT * 
                FROM Table1 
                WHERE (ColA = paramA) and (ColC between paramFromC and paramToC))  AS t1 
        GROUP BY t1.ColA, t1.ColB)  

解决方案：使用Ctznkane的答案，我发现了这个骇人的解决方案：

SELECT TOP 2 SUMMEDVALUE, ColA, ColB, ColC, ColD
FROM (SELECT A.ColA, A.ColB, A.ColC, A.ColD, (A.ColD+B.ColD) as SUMMEDVALUE
      FROM Table1 A
      INNER JOIN Table1 B 
      ON A.ColA=B.ColA AND A.ColC=B.ColC AND t1.ColB<>t2.ColB) 
ORDER BY SUMMEDVALUE DESC

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如果您正在寻找一对行，那么您应该将表本身连接起来

SELECT (A.COLD+B.COLD) SUMMEDVALUE, A.COLC, A.COLB, B.COLB, A.COLD, B.COLD
FROM TABLE1 A
    INNER JOIN TABLE1 B ON A.COLA=B.COLA AND A.COLC=B.COLC AND A.COLB<>B.COLB

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谢谢我更新了我的帖子，加入了我用你的答案找到的解决方案。