Sql 类似的

我有5张桌子：

 Artists (artistID: int, name: varchar(255))
 SimilarArtists (artistID: int, simArtistID: int, weight: int)
 Albums (albumID: int, artistID: int, name: varchar(255))
 Tracks (trackID: int, artistID: int, name: varchar(255), length: int)
 TrackLists (albumID: int, trackID: int, trackNum: int)

找到所有与莫格威更相似而非涅盘的艺术家的名字（这意味着他们与莫格威的相似程度更大）

暴力查询：），请检查空值

select * from (  
  select 
    (select weight from similiarartists sa, artists aa where sa.simartistid = aa.artistid and sa.artistid = a.artistid and aa.name = 'Nirvana') nirvana,
    (select weight from similiarartists sa, artists aa where sa.simartistid = aa.artistid and sa.artistid = a.artistid and aa.name = 'Mogwai') mogwai,
    a.*
 from artists a
) where a.mogwai > a.nirvana

---

这是我的尝试

select *
from artists a
left join 
(select sa.artistid, weight from similiarartists sa, artists aa where sa.simartistid =  aa.artistid and sa.artistid = a.artistid and aa.name = 'Nirvana') nirvana on nirvana.artistid = a.artistid
left join 
(select sa.artistid, weight from similiarartists sa, artists aa where sa.simartistid = aa.artistid and sa.artistid = a.artistid and aa.name = 'Mogwai') mogwai on mogwai.artistid = a.artistid
where mogwai.weight > nirvana.weight;

---

没有足够的信息来回答这个问题。请提供一些样本数据。特别是，表

是否是可交换的，也就是说，如果表中的（A，B）是（B，A）？而且，不在表中是不是证明相似性是
0
还是表中的所有对？
select *
from artists a
left join 
(select sa.artistid, weight from similiarartists sa, artists aa where sa.simartistid =  aa.artistid and sa.artistid = a.artistid and aa.name = 'Nirvana') nirvana on nirvana.artistid = a.artistid
left join 
(select sa.artistid, weight from similiarartists sa, artists aa where sa.simartistid = aa.artistid and sa.artistid = a.artistid and aa.name = 'Mogwai') mogwai on mogwai.artistid = a.artistid
where mogwai.weight > nirvana.weight;