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Sql 选择一行,该行的列在日期范围内具有最大值_Sql_Oracle - Fatal编程技术网

Sql 选择一行,该行的列在日期范围内具有最大值

Sql 选择一行,该行的列在日期范围内具有最大值,sql,oracle,Sql,Oracle,请原谅我提出了一个类似的问题。请考虑以下事项: date value 18/5/2010, 1 pm 40 18/5/2010, 2 pm 20 18/5/2010, 3 pm 60 18/5/2010, 4 pm 30 18/5/2010, 5 pm 60 18/5/2010, 6 pm 25 19/5/2010, 6 pm 300 19/5/2010, 6

请原谅我提出了一个类似的问题。请考虑以下事项:

date                 value

18/5/2010, 1 pm        40
18/5/2010, 2 pm        20
18/5/2010, 3 pm        60
18/5/2010, 4 pm        30
18/5/2010, 5 pm        60
18/5/2010, 6 pm        25 
19/5/2010, 6 pm        300 
19/5/2010, 6 pm        450 
19/5/2010, 6 pm        375 
20/5/2010, 6 pm        250 
20/5/2010, 6 pm        310 
查询是为了获取每天的日期和值,以便该天获得的值为最大值。如果在该天重复最大值,则选择最小的时间戳。结果应该是:

18/5/2010, 3 pm        60
19/5/2010, 6 pm        450
20/5/2010, 6 pm        310
查询应采用如下所示的日期范围,并以上述方式查找该范围的结果:

在哪里 日期>=截止日期“2010年3月26日”、“年月日”和
日期<截止日期'27/03/2010','DD/MM/yyyyy'

我没有尝试过这个,但我想你想要的是:

select max(date)
from  table
where date >= to_date('26/03/2010','DD/MM/YYYY') AND date < to_date('27/03/2010','DD/MM/YYYY')
group by trunc(date)

我没有试过,但我想你想要的是:

select max(date)
from  table
where date >= to_date('26/03/2010','DD/MM/YYYY') AND date < to_date('27/03/2010','DD/MM/YYYY')
group by trunc(date)

如果提供CREATETABLE和INSERT,那么提供测试答案就容易多了

create table i (i_dt date, i_val number);

insert into i values (to_date('18/5/2010 1pm','dd/mm/yyyy hham'),        40);
insert into i values (to_date('18/5/2010 2pm','dd/mm/yyyy hham'),        20);
insert into i values (to_date('18/5/2010 3pm','dd/mm/yyyy hham'),        60);
insert into i values (to_date('18/5/2010 4pm','dd/mm/yyyy hham'),        30);
insert into i values (to_date('18/5/2010 5pm','dd/mm/yyyy hham'),        60);
insert into i values (to_date('18/5/2010 6pm','dd/mm/yyyy hham'),        25 );
insert into i values (to_date('19/5/2010 6pm','dd/mm/yyyy hham'),        300 );
insert into i values (to_date('19/5/2010 6pm','dd/mm/yyyy hham'),        450 );
insert into i values (to_date('19/5/2010 6pm','dd/mm/yyyy hham'),        375 );
insert into i values (to_date('20/5/2010 6pm','dd/mm/yyyy hham'),        250 );
insert into i values (to_date('20/5/2010 6pm','dd/mm/yyyy hham'),        310 );

select i_dt, i_val from 
   (select i.*, rank() over (partition by trunc(i_dt) order by i_val desc, i_dt asc) rn 
   from i) 
where rn = 1;

如果提供CREATETABLE和INSERT,那么提供测试答案就容易多了

create table i (i_dt date, i_val number);

insert into i values (to_date('18/5/2010 1pm','dd/mm/yyyy hham'),        40);
insert into i values (to_date('18/5/2010 2pm','dd/mm/yyyy hham'),        20);
insert into i values (to_date('18/5/2010 3pm','dd/mm/yyyy hham'),        60);
insert into i values (to_date('18/5/2010 4pm','dd/mm/yyyy hham'),        30);
insert into i values (to_date('18/5/2010 5pm','dd/mm/yyyy hham'),        60);
insert into i values (to_date('18/5/2010 6pm','dd/mm/yyyy hham'),        25 );
insert into i values (to_date('19/5/2010 6pm','dd/mm/yyyy hham'),        300 );
insert into i values (to_date('19/5/2010 6pm','dd/mm/yyyy hham'),        450 );
insert into i values (to_date('19/5/2010 6pm','dd/mm/yyyy hham'),        375 );
insert into i values (to_date('20/5/2010 6pm','dd/mm/yyyy hham'),        250 );
insert into i values (to_date('20/5/2010 6pm','dd/mm/yyyy hham'),        310 );

select i_dt, i_val from 
   (select i.*, rank() over (partition by trunc(i_dt) order by i_val desc, i_dt asc) rn 
   from i) 
where rn = 1;

您正在聚合数据,因此请使用分组和聚合函数。您可以添加任何您想要的where子句,但我在中复制了您的where子句,更改了日期以便选中每条记录。借用Gary的create table和insert语句:

SQL> select min(i_dt) keep (dense_rank last order by i_val) i_dt
  2       , max(i_val) i_val
  3    from i
  4   where i_dt >= to_date('26/03/2010','dd/mm/yyyy')
  5     and i_dt < to_date('27/05/2010','dd/mm/yyyy')
  6   group by trunc(i_dt)
  7  /

I_DT                     I_VAL
------------------- ----------
18-05-2010 15:00:00         60
19-05-2010 18:00:00        450
20-05-2010 18:00:00        310

3 rows selected.
问候,,
Rob.

您正在聚合数据,因此请使用分组和聚合功能。您可以添加任何您想要的where子句,但我在中复制了您的where子句,更改了日期以便选中每条记录。借用Gary的create table和insert语句:

SQL> select min(i_dt) keep (dense_rank last order by i_val) i_dt
  2       , max(i_val) i_val
  3    from i
  4   where i_dt >= to_date('26/03/2010','dd/mm/yyyy')
  5     and i_dt < to_date('27/05/2010','dd/mm/yyyy')
  6   group by trunc(i_dt)
  7  /

I_DT                     I_VAL
------------------- ----------
18-05-2010 15:00:00         60
19-05-2010 18:00:00        450
20-05-2010 18:00:00        310

3 rows selected.
问候,,
罗布。

谢谢你的回复。但是,当我对超过1天的日期范围使用此查询时:其中date>=to_date'18/03/2010'、'DD/MM/YYYY'和date=to_date'18/03/2010'、'DD/MM/YYYY'和date