在SQL Server的单个列中计算3个值

我有一列值是从0，1，2看下面

0 = no, 1 = yes and 2 is waiting

我只想显示yes no和waiting where

adminid=1468

 IsVerified        AdminId
    0               1468
    0               1475  
    1               1468 
    1               1468
    1               1468 
    1               1468 
    1               1475
    2               1468
    2               1466

No    Yes    Waiting   AdminId
1      4       1        1468

我想将其显示为where

adminid=1468

 IsVerified        AdminId
    0               1468
    0               1475  
    1               1468 
    1               1468
    1               1468 
    1               1468 
    1               1475
    2               1468
    2               1466

No    Yes    Waiting   AdminId
1      4       1        1468

到目前为止，我已经使用了

SELECT     
    COUNT(s.IsVerified) AS [Yes]
    ,COUNT(s.IsVerified) AS [No]
    ,COUNT(s.IsVerified) AS [Waiting]
    ,g.AdminId
FROM    
    tbl_Squad s, tbl_Match m, tbl_Group g
WHERE   
    m.GroupId = g.GroupId          
    --AND g.AdminId=@AdminId
    AND g.AdminId=1468          
GROUP BY         
    s.IsVerified

---

但是它给出了三行，而我只想要一行，我错了

select sum(case when s.isverified = 0 then 1 else 0 end) no
, sum(case when s.isverified = 1 then 1 else 0 end) yes
, sum(case when s.isverified = 2 then 1 else 0 end) waiting

from tbl_squad s join tbl_group g on s.groupid = g.groupid

where g.adminid = 1468

---

像这样的方法应该会奏效：

select sum(case when s.isverified = 0 then 1 else 0 end) no
, sum(case when s.isverified = 1 then 1 else 0 end) yes
, sum(case when s.isverified = 2 then 1 else 0 end) waiting

from tbl_squad s join tbl_group g on s.groupid = g.groupid

where g.adminid = 1468

-旧式逗号分隔的表格列表样式已随ANSI-92 SQL标准（20多年前）而终止-旧式逗号分隔的表格列表样式已随ANSI-92 SQL标准（20多年前）而终止