Sql 合并多个计数
我正在尝试组合这组Sql 合并多个计数,sql,join,count,Sql,Join,Count,我正在尝试组合这组查询。 我已经做了搜索,但是我的查询有一些连接,它变得复杂了,有人能帮忙吗 select count(DISTINCT p.products_id) as count from (products p) join (products_to_categories p2c) on (p.products_id = p2c.products_id)
查询
。
我已经做了搜索,但是我的查询
有一些连接
,它变得复杂了,有人能帮忙吗
select count(DISTINCT p.products_id) as count from (products p)
join (products_to_categories p2c)
on (p.products_id = p2c.products_id)
left join (specials s)
on (p.products_id = s.products_id)
left join (products_attributes pa)
on (p.products_id = pa.products_id)
left join (products_options_values pv)
on (pa.options_values_id = pv.products_options_values_id)
left join (products_stock ps)
on (p.products_id=ps.products_id and pv.products_options_values_id = ps.products_options_values_id2)
INNER JOIN products_specifications ps10 ON p.products_id = ps10.products_id INNER JOIN products_specifications ps17 ON p.products_id = ps17.products_id where p.products_status = '1' and ps.products_stock_quantity>0 and p2c.categories_id in (72,1,23,47,48,49,74,24,33,34,35,77,25,46,45,44,40,41,42,43,76,78,83,50,52,81,79,2,54,60,82,53,57,58,55,61,62,63,75,56,64,65,66,67,68,69,70,71,84,80) AND ps10.specification in ('Meisje') AND ps10.specifications_id = '10'
AND ps10.language_id = '1'
and products_options_values_name in ( 80,"18M/80cm","8-12 mnd","9m","12m","9-12m","9M","12M" ) AND ps17.specification in ('Overhemd', 'Polo') AND ps17.specifications_id = '17'
AND ps17.language_id = '1'
好的,您的查询包含一些冗余,因为它们连接在select和where子句中都未使用的表。我已经在下面的解决方案中删除了这些。我还重新组织了其余的联接,将所有强制联接放在任何可选联接之前
select ps10.specification, count(DISTINCT p.products_id) as [count]
from products p
join products_to_categories p2c on p.products_id = p2c.products_id
join products_specifications ps10 ON p.products_id = ps10.products_id
join products_specifications ps17 ON p.products_id = ps17.products_id
left join products_stock ps on p.products_id=ps.products_id and pv.products_options_values_id = ps.products_options_values_id2
where p.products_status = '1' and ps.products_stock_quantity > 0
and p2c.categories_id in (72,1,23,47,48,49,74,24,33,34,35,77,25,46,45,44,40,41,42,43,76,78,83,50,52,81,79,2,54,60,82,53,57,58,55,61,62,63,75,56,64,65,66,67,68,69,70,71,84,80)
and ps10.specification in ('Meisje', 'Jongen', 'Unisex')
and ps10.specifications_id = '10'
and ps10.language_id = '1'
and products_options_values_name in ( 80,"18M/80cm","8-12 mnd","9m","12m","9-12m","9M","12M")
and ps17.specification in ('Overhemd', 'Polo')
and ps17.specifications_id = '17'
and ps17.language_id = '1'
GROUP BY ps10.specification
ORDER BY ps10.specification
这将产生以下输出:
specification | count
Jongen 93
Maisje 245
Unisex 36
(这些数字可能有点假)
希望这有帮助我已经想出了这个办法,而且似乎很管用 输出是
count1 count2 count3
------------------------
10 0 2
@john bingham“您的查询包含一些冗余”
你能帮我减少这个查询的冗余吗
select
count(DISTINCT if(ps10.specification in ('Meisje'),p.products_id,NULL)) as count1,
count(DISTINCT if(ps10.specification in ('Jongen'),p.products_id,NULL)) as count2,
count(DISTINCT if(ps10.specification in ('Unisex'),p.products_id,NULL)) as count3
from
(products p)
join
(products_to_categories p2c) on (p.products_id = p2c.products_id)
left join
(specials s) on (p.products_id = s.products_id)
left join
(products_attributes pa) on (p.products_id = pa.products_id)
left join
(products_options_values pv) on (pa.options_values_id = pv.products_options_values_id)
left join
(products_stock ps) on (p.products_id = ps.products_id
and pv.products_options_values_id = ps.products_options_values_id2)
inner join
products_specifications ps10 ON p.products_id = ps10.products_id
where
p.products_status = '1'
and ps.products_stock_quantity > 0
and p2c.categories_id in (72,1,23,47,48,49,74,24,33,34,35,77,25,46,45,44,40,41,42,43,76,78,83,50,52,81,79,2,54,60,82,53,57,58,55,61,62,63,75,56,64,65,66,67,68,69,70,71,84,80)
and ps10.specifications_id = '10'
and ps10.language_id = '1'
这些查询有什么不同?另外,请粘贴您期望的输出。它是mysql,不同之处在于ps10.specification in('meije')、ps10.specification in('Jongen')、ps10.specification in('Unisex')预期输出为计数1 10 1有时它需要加入20个计数,因此union不是选项I获取此错误#1054-where子句中的未知列“products_options_values_name”
count1 count2 count3
------------------------
10 0 2
select
count(DISTINCT if(ps10.specification in ('Meisje'),p.products_id,NULL)) as count1,
count(DISTINCT if(ps10.specification in ('Jongen'),p.products_id,NULL)) as count2,
count(DISTINCT if(ps10.specification in ('Unisex'),p.products_id,NULL)) as count3
from
(products p)
join
(products_to_categories p2c) on (p.products_id = p2c.products_id)
left join
(specials s) on (p.products_id = s.products_id)
left join
(products_attributes pa) on (p.products_id = pa.products_id)
left join
(products_options_values pv) on (pa.options_values_id = pv.products_options_values_id)
left join
(products_stock ps) on (p.products_id = ps.products_id
and pv.products_options_values_id = ps.products_options_values_id2)
inner join
products_specifications ps10 ON p.products_id = ps10.products_id
where
p.products_status = '1'
and ps.products_stock_quantity > 0
and p2c.categories_id in (72,1,23,47,48,49,74,24,33,34,35,77,25,46,45,44,40,41,42,43,76,78,83,50,52,81,79,2,54,60,82,53,57,58,55,61,62,63,75,56,64,65,66,67,68,69,70,71,84,80)
and ps10.specifications_id = '10'
and ps10.language_id = '1'