Sql 将多行与合并合并

使用SQL Server 2012

我有下表：

Id      Description 
6192    Salzburg
6193    Salzburg
6194    Salzburg
6196    Innsbruck
6197    Innsbruck
6198    Innsbruck
6199    Innsbruck
6201    Bregenz
6202    Bregenz
6203    Bregenz

我想选择每个不同的“描述”，将所有Id放在一个字符串中：

    Description     Ids
    Salzburg        '6192,6193,6194'
    Innsbruck       '6196,6197,6198'

我在这个网站上看到了一些类似的代码[，但出于我的目的，我还没有找到它（不想使用XML路径！）。以下是我迄今为止尝试过的内容：

DECLARE @ids AS Nvarchar(MAX)
SELECT  @ids = COALESCE(@ids + ',', '') + CAST(t.Id AS nvarchar(5))
    FROM (SELECT tmp.Id FROM (SELECT id, [Description] FROM tblMasterPropValues WHERE IdCategory = 253 AND IsActive = 1) as tmp
        WHERE [Description] = tmp.[Description]) AS t
SELECT @ids
--SELECT DISTINCT [Description], @ids AS IDs FROM tblMasterPropValues WHERE IdCategory = 253 AND IsActive = 1 AND Id IN (@ids)

---

我真的想不起来了，非常感谢您的帮助。

您可以尝试使用

STUFF（）

函数

SELECT description,  Ids = STUFF(
             (SELECT ',' + Id
              FROM tblMasterPropValues t1
              WHERE t1.description = t2.description
              FOR XML PATH (''))
             , 1, 1, '') from tblMasterPropValues t2
group by description;

---

因为

For XML PATH（）

是正确的子句，所以您可以执行以下操作：

SELECT DISTINCT v.description, STUFF(v1.ids, 1, 1, '''') + '''' 
FROM tblMasterPropValues v CROSS APPLY
     (SELECT ', '+ CAST(v1.Id AS VARCHAR(255))
      FROM tblMasterPropValues v1
      WHERE v1.description = v.description 
      FOR XML PATH('')
     ) v1(ids);

试试这个：

DECLARE @Table TABLE(ID INT, Description VARCHAR(25))
INSERT INTO @Table
VALUES (6192,'Salzburg' )
,(6193,'Salzburg' )
,(6194,'Salzburg' )
,(6196,'Innsbruck')
,(6197,'Innsbruck')
,(6198,'Innsbruck')
,(6199,'Innsbruck')
,(6201,'Bregenz'     )
,(6202,'Bregenz'     )
,(6203,'Bregenz'     )

查询：

SELECT DISTINCT T2.Description, 
    SUBSTRING(
        (
            SELECT ','+CAST(T1.ID AS VARCHAR)  AS [text()]
            FROM @Table T1
            WHERE T1.Description = T2.Description
            ORDER BY T1.Description
            FOR XML PATH ('')
        ), 2, 1000) [Ids]
FROM @Table T2

Description Ids
Bregenz     6201,6202,6203
Innsbruck   6196,6197,6198,6199
Salzburg    6192,6193,6194

结果：

SELECT DISTINCT T2.Description, 
    SUBSTRING(
        (
            SELECT ','+CAST(T1.ID AS VARCHAR)  AS [text()]
            FROM @Table T1
            WHERE T1.Description = T2.Description
            ORDER BY T1.Description
            FOR XML PATH ('')
        ), 2, 1000) [Ids]
FROM @Table T2

Description Ids
Bregenz     6201,6202,6203
Innsbruck   6196,6197,6198,6199
Salzburg    6192,6193,6194

---

您也可以通过使用递归CTE来实现

DECLARE @tblMasterPropValues TABLE (Id INT, Description VARCHAR(20))
INSERT INTO @tblMasterPropValues VALUES
(6192 , 'Salzburg'),
(6193 , 'Salzburg'),
(6194 , 'Salzburg'),
(6196 , 'Innsbruck'),
(6197 , 'Innsbruck'),
(6198 , 'Innsbruck'),
(6199 , 'Innsbruck'),
(6201 , 'Bregenz'),
(6202 , 'Bregenz'),
(6203 , 'Bregenz')



;WITH Tbl AS 
(
    SELECT 
        *, 
        ROW_NUMBER() OVER(PARTITION BY Description ORDER BY Id) AS RN,
        COUNT(*) OVER(PARTITION BY Description) AS CNT
    FROM @tblMasterPropValues 
)
, Rcr AS (
    SELECT *, CAST(Id AS varchar(max)) Ids 
    FROM Tbl WHERE RN = 1
        UNION ALL
    SELECT T.*, Rcr.Ids + ',' + CAST(T.Id AS VARCHAR(10)) Ids 
    FROM Rcr 
        INNER JOIN Tbl T ON T.RN = Rcr.RN + 1 and Rcr.Description = T.Description
)
SELECT RN, Description, Ids FROM Rcr 
WHERE RN = CNT

结果:

Description          Ids
-------------------- -----------------------
Salzburg             6192,6193,6194
Innsbruck            6196,6197,6198,6199
Bregenz              6201,6202,6203

---

我不想使用XML路径！我将使用您的解决方案，即使它使用XML路径。非常感谢。这很好。我正在准备一个使用光标的解决方案，但要避免使用光标。从2020年开始，使用此解决方案！TKS！