在SQL中查找运行总和（Access 07-10）

我正试图找到一个连续的总数。当我运行此程序时，每次帐户在两周内进行购买时，我都会得到一笔钱，而不是总数。我想回答的问题是，每个账户在头两周内的支出是多少

SELECT 
    dbo_AAS.Account, 
    dbo_AM.ED, 
    ([dbo_AM].[ED]+14) AS TwoWeeks, 
    dbo_AAS.RD, 
    Sum(Abs([dbo_AAS].[WA])) AS ABSWA    
FROM dbo_AAS 
INNER JOIN dbo_AM 
    ON dbo_AAS.Account = dbo_AM.Account
GROUP BY 
    dbo_AAS.Account, 
    dbo_AM.ED, 
    dbo_AAS.RD
HAVING ((
    (dbo_AM.ED) Is Not Null) 
    AND ((dbo_AAS.RD) Between [dbo_AM].[ED] And [dbo_AM].[ED]+14));

结果是：

+-------+----------+----------+----------+-----+
|Account|ED        |TwoWeeks  |RD        |ABSWA|
+-------+----------+----------+----------+-----+
|34     |11/23/2013|12/07/2013|11/23/2013|18   |
+-------+----------+----------+----------+-----+
|34     |11/23/2013|12/07/2013|11/27/2013|30   |
+-------+----------+----------+----------+-----+
|34     |11/23/2013|12/07/2013|12/02/2013|15   |
+-------+----------+----------+----------+-----+
|34     |11/23/2013|12/07/2013|12/05/2013|20   |
+-------+----------+----------+----------+-----+

预期结果

+-------+----------+----------+--+-----+
|Account|ED        |TwoWeeks  |RD|ABSWA|
+-------+----------+----------+--+-----+
|34     |11/23/2013|12/07/2013|* |83   |
+-------+----------+----------+--+-----+

---

您是按RD分组的，所以这将为RD中的每个值提供一行。将该字段从GROUPBY语句中去掉，您应该会得到答案。您还必须将其从SELECT语句中删除，否则它将向您抛出错误

SELECT dbo_AAS.Account,
       dbo_AM.ED,
       ([dbo_AM].[ED]+14) AS TwoWeeks,
       Sum(Abs([dbo_AAS].[WA])) AS ABSWA
FROM dbo_AAS
INNER JOIN dbo_AM
   ON dbo_AAS.Account = dbo_AM.Account
WHERE dbo_AAS.RD BETWEEN '11/23/2013' AND '12/05/2013'
GROUP BY dbo_AAS.Account, dbo_AM.ED
HAVING (((dbo_AM.ED) Is Not Null) AND
       ((dbo_AAS.RD) Between [dbo_AM].[ED] And [dbo_AM].[ED]+14));

---

只需完全删除RD即可。

一个子查询就成功了。谢谢你们的帮助

选择[%$@_别名].帐户，dbo_AM.FN，dbo_AM.LN，总和[%$@_别名].abswa为WA，dbo_AM.ED，[dbo_AM].[ED]+14为两周 从中选择dbo_AAS.Account、dbo_AM.ED、dbo_AAS.RD、SumAbs[dbo_AAS].[WS]作为ABSWA

从dbo_AAS内部连接dbo_AM ON dbo_AAS.Account=dbo_AM.Account

按dbo_AAS.Account、dbo_AM.ED、dbo_AAS.RD分组

在[dbo_AM].[ED]和[dbo_AM].[ED]+14之间有dbo_AAS.RD 作为[%$@\u别名]在[%$@\u别名]上的内部联接dbo\u AM。帐户=dbo\u AM.Account

---

按[%$@_别名]分组。帐户、dbo_AM.FN、dbo_AM.LN、dbo_AM.ED、[dbo_AM].[ED]+14

感谢您纠正我的错误。当我从组中删除RD时，我收到错误，您尝试执行的查询未将指定的表达式“RD”作为聚合函数的一部分。这就是为什么我说也从SELECT语句中删除它。删除RD时，结果ABSWA不限于两周的时间限制：当RD为已删除结果ABSWA不限于两周的时间限制：@user3120577只需在WHERE中添加条件和所需日期。