Sql 哪个SELECT语句将从表行中获取非零值？

如果我在一个27列的表中有多行，它们都是这样的整数

id_1    id_2    id_3    id_4    id_5    id_6    id_7    id_8    id_9    id_10   id_11   id_12   id_13   id_14   id_15   id_16   id_17   id_18   id_19   id_20   id_21   id_22   id_23   id_24   id_25   id_26   id_27
0       2       0       4       5       0       0       8       0       10      0       0       0       14      0       0       17      0       0       0       21      0       0       0       0       0       0

我想运行一个SELECT语句，得到最多8列>零的列。永远不会超过8列。什么是最好的方法，或者至少是功能性的方法？如果没有8个大于0的值，则允许为空。因此，从上面得到的表格将是

col1 col2 col3 col4 col5 col6 col7 col8
2    4    5    8    10   14   17   21

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如果您能忍受列中的结果，那么这是一种简单的方法：

select top 8 v.col
from table t cross apply
     values ((t.id_1), (t.id_2), . . ., (t.id_27)) as v(col)
where v.col <> 0;

所有数据都是8。如果希望每行8个，则需要行标识符。您还可以使用窗口功能：

select t.id, v.col
from (select t.id, v.col,
             row_number() over (partition by t.id order by (select null)) as seqnum
      from table t cross apply
           values ((t.id_1), (t.id_2), . . ., (t.id_27)) as v(col)
      where col <> 0
     ) t
where seqnum <= 8;

最后，您可以将它们转回到一行。我倾向于使用条件聚合：

select t.id,
       max(case when seqnum = 1 then v.col end) as val1,
       max(case when seqnum = 2 then v.col end) as val2,
       max(case when seqnum = 3 then v.col end) as val3,
       max(case when seqnum = 4 then v.col end) as val4,
       max(case when seqnum = 5 then v.col end) as val5,
       max(case when seqnum = 6 then v.col end) as val6,
       max(case when seqnum = 7 then v.col end) as val7,
       max(case when seqnum = 8 then v.col end) as val8
from (select t.id, v.col,
             row_number() over (partition by t.id order by (select null)) as seqnum
      from table t cross apply
           values ((t.id_1), (t.id_2), . . ., (t.id_27)) as v(col)
      where col <> 0
     ) t
where seqnum <= 8
group by id;

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我想我们可以通过程序的帮助来实现它。你想要每行8个值还是所有行8个值？如果是每行，是否有行标识符？@GordonLinoff没有标识符，但它是一个临时表，因此我可以在必要时添加一个。每行8个值，语法错误。我现在添加了一个名为id的标识符，我的表名为tester。这将如何改变你的脚本请？