Sql 一个表组中的一列与另一个表中的其他两列之和

我有两张桌子，第一张是

结果

ssn,date,scode,dcode,ppay,ipay
302609074,20180215,4002,1001,25,35
302609074,20180215,4006,1003,40,100
302609074,20181010,4002,1001,25,35
302609074,20181010,4006,1003,40,100
302609074,20190505,4002,1001,25,35
302609074,20190506,4006,1003,40,100
997600970,20190115,4001,1002,25,50
997600970,20190115,4001,1003,40,30
997600970,20190115,4004,1004,40,50
997600970,20190415,4002,1004,40,95
997600970,20190415,4003,1005,40,100
997600970,20181212,4004,1001,25,47
997600970,20181213,4004,1001,25,47
874136439,20190808,4002,1002,25,50
874136439,20190808,4002,1003,40,60
874136439,20190910,4002,1004,40,95
874136439,20190910,4002,1005,60,90
874136439,20191001,4003,1002,25,50
874136439,20191002,4003,1002,25,50
874136439,20191003,4003,1002,25,55
831287780,20190404,4001,1001,25,0
831287780,20190505,4003,1002,25,40
831287780,20190606,4004,1003,25,100
831287780,20190707,4006,1004,60,100
882861510,20190202,4005,1002,60,60
882861510,20190303,4002,1004,25,100
882861510,20190404,4005,1002,40,100
882861510,20190505,4002,1004,50,100
882861510,20190606,4005,1003,50,0
796235486,20190808,4001,1001,25,25
445139565,20180707,4002,1001,40,35
445139565,20190929,4002,1003,40,70
445139565,20190929,4002,1004,40,95
445139565,20190929,4002,1005,40,120
524246868,20190909,4006,1005,100,100
524246868,20190910,4006,1005,100,100
416806352,20190818,4003,1001,25,30
416806352,20190818,4003,1005,50,100
946883650,20190717,4001,1004,25,100
946883650,20190817,4001,1004,25,100
946883650,20190917,4006,1004,50,132
946883650,20191002,4006,1004,50,132
129141378,20190909,4001,1002,25,50
129141378,20190909,4001,1003,0,100
129141378,20190909,4001,1004,0,125
129141378,20190909,4001,1005,0,150
950022926,20181111,4006,1004,182,0
950022926,20190323,4006,1004,100,82
950022926,20190623,4006,1004,0,182
799023031,20190930,4005,1003,50,100
719301054,20190110,4001,1003,25,75
719301054,20190210,4001,1003,25,75
719301054,20190310,4001,1003,25,75
316517393,20190626,4005,1005,0,0
148694321,20190102,4006,1002,40,72
148694321,20190203,4006,1002,40,72
148694321,20190304,4006,1002,40,72
332124842,20190405,4004,1001,25,47
332124842,20190506,4004,1002,25,80
332124842,20190607,4004,1003,25,107

及 诊断

scode、dcode、charge
40011001,50
40011002,75
40011003100
40011004125
40011005150
40021001,60
40021002,85
40021003110
40021004135
40021005160
40031001,55
40031002,80
40031003105
40031004130
40031005155
40041001,72
40041002102
40041003132
40041004162
40041005192
40051001,90
40051002140
40051003190
40051004240
40051005290
40061001,77
40061002112
40061003147
40061004182
40061005217

我需要在同一日期获得每个SSN的金额（费用）。例如来自

302609074,20180215,4002,1001,25,35
302609074,20180215,4006,1003,40,100

我想从日期为20180215的表诊断中获得总和（费用）=60+147=207

到目前为止，我试过的都不管用。例如，我得到：

ELECT Z.date, Z.ssn, TotalCharges
FROM (  
        (SELECT ssn,date,scode,dcode
         FROM outcome
        ) Z
        JOIN 
        (SELECT scode, dcode, charge, SUM(charge) TotalCharges
         FROM diagnosis
        ) U
        ON (U.scode = Z.scode AND U.dcode = Z.dcode)
     )
     GROUP BY Z.date, Z.ssn;

---

出现错误ORA-00937:没有一个组函数

为什么要使用这么多子查询

SELECT o.date, o.ssn, SUM(d.charge)
FROM outcome o JOIN
     diagnosis d
     ON d.scode = o.scode AND d.dcode = o.dcode
GROUP BY o.date, o.ssn;

如果子查询中有

分组依据

，则您的查询也可能有效