Sql google大查询对多个列的唯一组合进行排序

我们已经有一个网站的所有推荐表：每个推荐一个条目

String : referral
String : target
integer: date

现在，我们希望使用大查询根据计数对所有转介进行排序，如：

referral       : target,         count:

google.com/... : welcome.html,   28353 
bing.com/...   : welcome.html,   5334 
gmail.com/...  : about.html,     343
...

---

大查询sql应该是什么？

如果我理解正确，那么：

SELECT COUNT(path) AS path_count, path
FROM (
  SELECT concat(referrer, target) AS path
  FROM [mydataset.referrallog])
GROUP BY path ORDER BY path_count DESC;

---

如果我猜对了，那么：

SELECT COUNT(path) AS path_count, path
FROM (
  SELECT concat(referrer, target) AS path
  FROM [mydataset.referrallog])
GROUP BY path ORDER BY path_count DESC;

---

为什么不按两列进行分组

SELECT referral, target, COUNT(*) as cnt
FROM [mydataset.referrallog] 
GROUP BY referral, target
ORDER BY cnt DESC

---

为什么不按两列进行分组

SELECT referral, target, COUNT(*) as cnt
FROM [mydataset.referrallog] 
GROUP BY referral, target
ORDER BY cnt DESC

---

我必须删除distinct，这样它才能正确计数。选择count path，path FROM SELECT concatreferrer，target as path FROM[mydataset.referrallog]group by path，但此sql尚未根据count对结果进行排序。因此，最终答案是SELECT count path as path_count，path FROM SELECT concatreferrer，target as path FROM[mydataset.referrallog]按路径分组按路径排序按路径计数说明。用户1516770：如果您可以编辑您的原始答案，我将批准它！我必须删除distinct，这样它才能正确计数。选择count path，path FROM SELECT concatreferrer，target as path FROM[mydataset.referrallog]group by path，但此sql尚未根据count对结果进行排序。因此，最终答案是SELECT count path as path_count，path FROM SELECT concatreferrer，target as path FROM[mydataset.referrallog]按路径分组按路径排序按路径计数说明。用户1516770：如果您可以编辑您的原始答案，我将批准它！