Sql 使用oracle获取范围内的数据

请帮我解决这个问题

我有一个包含用户每天签入（checktype=I）和签出（checktype=0）时间的表，我希望获得特定日期范围内每个用户的签入总时间>08:00 AM

我正在使用下面的查询，但每个查询只处理一天，不在范围内，因此我必须使用javascript循环以获取每个用户的延迟量（>08:00 am），例如从2012年6月1日到2012年6月6日

请帮助我在一次查询中获得从2012年6月1日到2012年6月6日每个用户（ex:userid 708）在上午8:00以上签入的金额（计数）

with tt as 
     ( 
     select TO_DATE('01/06/2012 08:00:00','dd/mm/yyyy hh24:mi:ss') date1 , 
            checktime date2 
     from 
            checkinout 
     where 
            userid = '708' and 
            to_char(checktime,'dd/mm/yyyy') = '01/06/2012' and 
            checktype='I'  -- checktype I is check in
     ) , t2 as 
            ( 
               select numtodsinterval(date2 - date1,'day') dsinterval from tt 
            ) 
            select extract(hour from dsinterval) || ' hours ' || 
                   extract(minute from dsinterval) || ' minutes ' || 
                   round(extract(second from dsinterval)) || ' seconds' late from t2

---

考虑以下示例，在此基础上，您可以编写自己的逻辑

WITH tbl AS
     (SELECT SYSDATE dt
        FROM DUAL
      UNION
      SELECT SYSDATE + (1 + (10 / 1440))
        FROM DUAL
      UNION
      SELECT SYSDATE + (2 + (12 / 1440))
        FROM DUAL
      UNION
      SELECT SYSDATE + (3 + (13 / 1440))
        FROM DUAL
      UNION
      SELECT SYSDATE + (6 + (15 / 1440))
        FROM DUAL
      UNION
      SELECT SYSDATE + (8 + (18 / 1440))
        FROM DUAL)
SELECT    EXTRACT (HOUR FROM dsinterval)
       || ' hours '
       || EXTRACT (MINUTE FROM dsinterval)
       || ' minutes '
       || ROUND (EXTRACT (SECOND FROM dsinterval))
       || ' seconds' late
  FROM (SELECT NUMTODSINTERVAL (dt1 - dt2, 'day') dsinterval
          FROM (SELECT TO_DATE (TO_CHAR (dt, 'DD/MM/YYYY') || ' 08:00:00',
                                'DD/MM/YYYY HH24:MI:SS'
                               ) dt1,
                       TO_DATE (TO_CHAR (dt, 'DD/MM/YYYY HH24:MI:SS'),
                                'DD/MM/YYYY HH24:MI:SS'
                               ) dt2
                  FROM tbl
                 WHERE dt BETWEEN SYSDATE + 2 AND SYSDATE + 5))

根据代码，您可以像

SELECT    EXTRACT (HOUR FROM dsinterval)
       || ' hours '
       || EXTRACT (MINUTE FROM dsinterval)
       || ' minutes '
       || ROUND (EXTRACT (SECOND FROM dsinterval))
       || ' seconds' late
  FROM (SELECT NUMTODSINTERVAL (dt1 - dt2, 'day') dsinterval
          FROM (SELECT TO_DATE (TO_CHAR (checktime , 'DD/MM/YYYY') || ' 08:00:00',
                                'DD/MM/YYYY HH24:MI:SS'
                               ) dt1,
                       TO_DATE (checktime, 'DD/MM/YYYY HH24:MI:SS') dt2
                  FROM checkinout
                 WHERE checktime BETWEEN start_date AND end_date 
                   AND checktype='I'))

---

我假设您想知道签入延迟了多少小时（即08:00之后）：

with t2 as (
select userid
      ,numtodsinterval(sum(checktime - (trunc(checktime)+8/24)),'day') dsinterval
      ,count(1) cnt
   from checkinout
  where userid='708'
    and checktime > trunc(checktime)+8/24
    and trunc(checktime) between to_date('01/06/2012','DD/MM/YYYY') and to_date('06/06/2012','DD/MM/YYYY')
    and checktype = 'I'
  group by  userid 
)
select extract(hour from dsinterval) || ' hours ' || 
       extract(minute from dsinterval) || ' minutes ' || 
       round(extract(second from dsinterval)) || ' seconds' late 
      ,cnt
   from t2;

查看我的测试用例

编辑：添加列“cnt”以显示次数