是否可以以这种格式显示两条SQL语句的结果?

是否可以以这种格式显示两条SQL语句的结果?,sql,oracle,Sql,Oracle,大家好,首先感谢大家关注这个问题 我有两条SQL语句,我想结合它们以某种格式提供结果 第一个SQL从数据库中的3个表中查找给定时间跨度的信息: SELECT substr(b.platz,4,2)||'-'||substr(b.platz,6,2)||'-'||substr(b.platz,8,3)||'-'||substr(b.platz,11,2) AS "Location", to_char(b.INV_DATUM, 'dd.mm.yyyy') AS "DateOfInventory

大家好,首先感谢大家关注这个问题

我有两条SQL语句,我想结合它们以某种格式提供结果

第一个SQL从数据库中的3个表中查找给定时间跨度的信息:

SELECT 
substr(b.platz,4,2)||'-'||substr(b.platz,6,2)||'-'||substr(b.platz,8,3)||'-'||substr(b.platz,11,2) AS "Location",  
to_char(b.INV_DATUM, 'dd.mm.yyyy') AS "DateOfInventory", 
b.INV_ZEIT AS "TimeOfInventory",
a.INV_USR AS "InventoriedBy",
(SELECT COUNT(*) FROM INVERGEBNIS a WHERE a.invnr = b.lfdnr) AS "NumberOfPIDs",
(SELECT COUNT(*) FROM INVERGEBNIS a WHERE a.invnr = b.lfdnr AND a.menge_soll != a.menge_ist) AS "NumberOfPIDsAdjusted"
FROM INVERGEBNIS a, INVAUFTRAG b, platz p
WHERE b.LFDNR = a.INVNR 
AND b.platz = p.platz_ID 
AND b.INV_DATUM >= '01.01.2019'
AND b.INV_DATUM <= '31.12.2019'
GROUP BY a.INVNR, Platz, to_char(b.INV_DATUM, 'dd.mm.yyyy'), b.INV_ZEIT, a.INV_USR, b.lfdnr
第二个SQL查找从第一个SQL调整的NumberOfPIDsAdjusted的结果:

    SELECT substr(b.platz,4,2)||'-'||substr(b.platz,6,2)||'-'||substr(b.platz,8,3)||'-'||substr(b.platz,11,2) AS "Location", 
a.ARTIKELNR AS "ArticleNumber",  
a.PALNR AS "PID", 
a.MENGE_SOLL AS "ExpectedQuantity", 
a.MENGE_IST AS "CountedQuantity", 
a.ABWEICH_ABS AS "Difference" 
FROM INVERGEBNIS a, INVAUFTRAG b, platz p
WHERE a.menge_soll != a.menge_ist 
AND a.invnr = b.lfdnr
AND b.INV_DATUM >= '01.01.2019'
AND b.INV_DATUM <= '31.12.2019'
GROUP BY a.INVNR, Platz, a.ARTIKELNR, a.PALNR, a.MENGE_SOLL, a.MENGE_IST, a.ABWEICH_ABS
我正在尝试将这两个SQL组合起来,以便显示具有某种意义的结果。 我尝试过加入工会,但没有成功

如果可能的话,我正在努力实现这一目标:

存货的位置日期存货的时间由NumberOfPIDs盘点NumberOfPIDs调整

Location        DateOfInventory TimeOfInventory InventoriedBy   NumberOfPIDs    NumberOfPIDsAdjusted
        ArticleNumber   PID         ExpectedQuantity    CountedQuantity Difference
S3-11-021-05    16.10.2019      08:31:17        JeEn            3               0
C1-08-011-04    23.08.2019      14:49:18        JeEn            4               0
K6-04-003-03    13.08.2019      11:06:26        JeRi            1               0
S4-01-002-02    22.08.2019      09:22:55        JeEn            3               1
        715111012       1286209156  16                  0               -16
K1-01-023-04    27.09.2019      12:36:58        JeRi            2               1
        148055064       1282100556  3                   0               -3
C1-02-030-04    28.08.2019      12:18:35        JeEn            5               5
        290090004       6538190978  0                   24              24
        290090004       7636034034  0                   24              24
        290090004       4130433752  0                   24              24
        290090004       3877101085  0                   24              24
        290090004       3970443099  0                   24              24
C1-07-014-02    22.08.2019      14:19:10        JeEn            3               0
S4-01-002-01    30.08.2019      12:44:10        JeEn            2               2
        520421012       2101052940  0                   10              10
        040331016       1273906464  6                   0               -6
再次感谢您抽出时间来看我的问题


JRidge

为什么有一个
INV_DATUM
(日期)列和一个单独的
INV_ZEIT
(时间存储为字符串)列?Oracle没有
日期时间
数据类型,
日期
数据类型始终存储年、月、日、时、分和秒组件,您可以只使用一列。在我们的数据库中,我们有两列,日期列的时间部分为00:00:00,时间保存在时间列中。从您的数据可以看出这一点;但是,我的观点是,您不应该这样做,应该将时间组件存储在
DATE
列中,而不是将
DATE
的时间组件设置为
00:00
,然后在单独的列中使用字符串。
Location        ArticleNumber   PID         ExpectedQuantity    CountedQuantity Difference
C1-02-030-04    290090004       6538190978  0                   24              24
C1-02-030-04    290090004       7636034034  0                   24              24
C1-02-030-04    290090004       4130433752  0                   24              24
C1-02-030-04    290090004       3877101085  0                   24              24
C1-02-030-04    290090004       3970443099  0                   24              24
K1-01-023-04    148055064       1282100556  3                   0               -3
S4-01-002-01    520421012       2101052940  0                   10              10
S4-01-002-01    040331016       1273906464  6                   0               -6
S4-01-002-02    715111012       1286209156  16                  0               -16
Location        DateOfInventory TimeOfInventory InventoriedBy   NumberOfPIDs    NumberOfPIDsAdjusted
        ArticleNumber   PID         ExpectedQuantity    CountedQuantity Difference
S3-11-021-05    16.10.2019      08:31:17        JeEn            3               0
C1-08-011-04    23.08.2019      14:49:18        JeEn            4               0
K6-04-003-03    13.08.2019      11:06:26        JeRi            1               0
S4-01-002-02    22.08.2019      09:22:55        JeEn            3               1
        715111012       1286209156  16                  0               -16
K1-01-023-04    27.09.2019      12:36:58        JeRi            2               1
        148055064       1282100556  3                   0               -3
C1-02-030-04    28.08.2019      12:18:35        JeEn            5               5
        290090004       6538190978  0                   24              24
        290090004       7636034034  0                   24              24
        290090004       4130433752  0                   24              24
        290090004       3877101085  0                   24              24
        290090004       3970443099  0                   24              24
C1-07-014-02    22.08.2019      14:19:10        JeEn            3               0
S4-01-002-01    30.08.2019      12:44:10        JeEn            2               2
        520421012       2101052940  0                   10              10
        040331016       1273906464  6                   0               -6