SQL Server中两个不同分组的求和和和计数

我想打印每个帐户的总订单、交易金额和计数

运行下面的查询时，出现以下错误：

列“orders.order\u amount”在选择列表中无效，因为它不包含在聚合函数或GROUP BY子句中

我怎样才能解决这个问题

SELECT
    trans.account_id,
    SUM(trans.amount),
    COUNT(trans.account_id),
    orders.order_amount, 
    orders.order_count
FROM
    trans
FULL JOIN 
    (SELECT 
         [order].account_id,
         SUM([order].amount) as order_amount, 
         COUNT([order].account_id) as order_count
     FROM
         [order]
     GROUP BY 
         [order].account_id) AS orders ON (trans.account_id = orders.account_id)
GROUP BY
    trans.account_id
ORDER BY 
    trans.account_id;

Trans

表格：

trans_id  account_id  type  amount  balance  account   date
-----------------------------------------------------------------
1              1       a      88      213      75      1995-03-24
7              1       b      156     66       75      1995-02-25

订单

表格

order_id  account_id  bank_to amount 
-------------------------------------
1              1       a      88       
7              1       b      156       

---

您需要将

订单。订单金额

和

订单。订单计数

添加到

分组依据

：

select trans.account_id,
       SUM(trans.amount),
       COUNT(trans.account_id),
       orders.order_amount, 
       orders.order_count
from trans
        FULL JOIN (
            select  [order].account_id,
                    SUM([order].amount) as order_amount, 
                    COUNT([order].account_id) as order_count

            from [order]

            GROUP BY [order].account_id


          ) as orders

          ON (trans.account_id = orders.account_id)

group by trans.account_id, orders.order_amount, orders.order_count
order by trans.account_id;

---

如果您认为帐户可以在任一表中，但不一定同时在两个表中，那么您将使用

full join

。如果是这样，您应该修复您的查询

我建议在

join

ing之前聚合这两个表。然后根据条件固定

订单：

select coalesce(t.account_id, o.account_id), t.trans_amount, t.trans_count,
       o.order_amount, o.order_count
from (select t.account_id, sum(t.amount) as trans_amount, count(*) as trans_count
      from trans t
      group by t.account_id
     ) t full join
     (select o.account_id,
             sum(o.amount) as order_amount, 
             count(o.account_id) as order_count
      from [order] o
      group by o.account_id
     ) o
     on t.account_id = o.account_id
order by coalesce(t.account_id, o.account_id);

请注意，通常不需要
完全连接。但是，如果需要，应该为其正确编写查询