两个表中的SQL内部联接只匹配一次

我正在努力找到一种有效的方法来自内联接一个有1m行的表

表t的别名为

t1

和

t2

：

Timestamp col1 col2

我想基于timestamp和col1进行内部连接，以便只匹配一次：

如果有多个匹配项，则从右表返回第一个匹配项

并且匹配的列已标记，不能用于下一次匹配

在伪代码中

for v in t1.col1:
   if t1.timestamp - t2.timestamp < 5 mins AND t2.mark == False AND t1.col1 = t2.col1:
       t2.mark = true <- don't know how to do this in SQL
       return t1.timestamp, t1.col1, t1.col2, t2.timestamp, t2.col2

样本输出数据：

open_time                  close_time              name open_price close_price
2020-11-16 01:07:38.147501 2020-11-16 01:53:17.690113 A 1.0         1.5

在“打开时间”列和“关闭时间”列中，它们在各自的列中是唯一的

任何行的打开时间和关闭时间之间都没有重叠。换句话说，对于第2行的打开时间，它必须晚于第1行的关闭时间

这可能与游标有关

---

为了简化这个问题，请考虑我有以下的记录：

 open_time                  close_time              name open_price close_price
2020-11-16 01:07:38.147501,2020-11-16 01:53:17.690113, a, 1
2020-11-16 01:07:38.147501,2020-11-16 01:53:03.217847, a, 1.1
2020-11-16 01:07:40.294957,2020-11-16 01:53:17.690113, a, 1.2
2020-11-16 01:07:40.294957,2020-11-16 01:53:03.217847, a, 1.3

---

如何使所有记录的打开时间和关闭时间不重叠？

我将此问题解释为两个表中存在重复项，并且希望将它们合并，因此只有一个重复的行匹配

可以通过枚举每个表中的行来解决此问题：

select . . .
from (select t1.*,
             row_number() over (partition by col, timestamp order by timestamp) as seqnum
      from t1
     ) t1 join
     (select t2.*,
             row_number() over (partition by col, timestamp order by timestamp) as seqnum
      from t2
     ) t2
     on t1.col = t2.col and
        t1.timestamp = t2.timestamp and
        t1.seqnum = t2.seqnum

---

请提供样品数据和预期结果。谢谢。更新的样本数据。这有意义吗@戈登林诺夫

select . . .
from (select t1.*,
             row_number() over (partition by col, timestamp order by timestamp) as seqnum
      from t1
     ) t1 join
     (select t2.*,
             row_number() over (partition by col, timestamp order by timestamp) as seqnum
      from t2
     ) t2
     on t1.col = t2.col and
        t1.timestamp = t2.timestamp and
        t1.seqnum = t2.seqnum