Sql 如果超过1个匹配项，请不要返回“未知”

我编写了一个怪物查询。我确信它可以被优化，我非常感谢对查询本身的任何评论/指导；但是，我有一个具体的问题：

我返回的数据有时会在多个列上重复：

+-------+------+----------+------+-------+--------+----------+-------+------+
| first | last |  deaID   | cert | count |  npi   | clientid | month | year |
+-------+------+----------+------+-------+--------+----------+-------+------+
| Alex  | Jue  | UNKNOWN  | MD   |    11 | 123123 |   102889 |     7 | 2012 |
| Alex  | Jue  | BJ123123 | MD   |    11 | 123123 |   102889 |     7 | 2012 |
+-------+------+----------+------+-------+--------+----------+-------+------+

正如您所看到的，除了deaID之外，所有字段都是相等的

在这种情况下，我只想返回：

+------+-----+----------+----+----+--------+--------+---+------+
|      |     |          |    |    |        |        |   |      |
+------+-----+----------+----+----+--------+--------+---+------+
| Alex | Jue | BJ123123 | MD | 11 | 123123 | 102889 | 7 | 2012 |
+------+-----+----------+----+----+--------+--------+---+------+

但是，如果没有重复项：

+-------+------+---------+------+-------+--------+----------+-------+------+
| first | last |  deaID  | cert | count |  npi   | clientid | month | year |
+-------+------+---------+------+-------+--------+----------+-------+------+
| Alex  | Jue  | UNKNOWN | MD   |    11 | 123123 |   102889 |     7 | 2012 |
+-------+------+---------+------+-------+--------+----------+-------+------+

那么我想保留它

总结 如果存在重复项，则删除所有具有“deaID=unknown”的记录；但是，如果只有1个匹配项，则返回该匹配项

问题: 如果存在1个匹配项，如何返回未知记录

以下是monster查询，以防有人感兴趣：

with ctebiggie  as (

select distinct
p.[IMS_PRESCRIBER_ID],
p.PHYSICIAN_NPI as MLISNPI,
a.CLIENT_ID,
p.MLIS_FIRSTNAME,
p.MLIS_LASTNAME,
p_address.IMS_DEA_NBR,
p.IMS_PROFESSIONAL_ID_NBR,
p.IMS_PROFESSIONAL_ID_NBR_src,
p.IMS_CERTIFICATION_CODE,
datepart(mm,a.RECEIVED_DATE) as [Month],
datepart(yyyy,a.RECEIVED_DATE) as [Year]

from

MILLENNIUM_DW_dev..D_PHYSICIAN p
left outer join
MILLENNIUM_DW_dev..F_ACCESSION_DAILY a
on a.REQUESTOR_NPI=p.PHYSICIAN_NPI
left outer join MILLENNIUM_DW_dev..D_PHYSICIAN_ADDRESS p_address
on p.PHYSICIAN_NPI=p_address.PHYSICIAN_NPI

where 
a.RECEIVED_DATE is not null
--and p.IMS_PRESCRIBER_ID is not null
--and p_address.IMS_DEA_NBR !='UNKNOWN'
and p.REC_ACTIVE_FLG=1
and p_address.REC_ACTIVE_FLG=1
and DATEPART(yyyy,received_date)=2012
  and DATEPART(mm,received_date)=7


group by 
p.[IMS_PRESCRIBER_ID],
p.PHYSICIAN_NPI,
p.IMS_PROFESSIONAL_ID_NBR,
p.MLIS_FIRSTNAME,
p.MLIS_LASTNAME,
p_address.IMS_DEA_NBR,
p.IMS_PROFESSIONAL_ID_NBR,
p.IMS_PROFESSIONAL_ID_NBR_src,
p.IMS_CERTIFICATION_CODE,
datepart(mm,a.RECEIVED_DATE),
datepart(yyyy,a.RECEIVED_DATE),
a.CLIENT_ID

)
,
ctecount as 
(select
 COUNT (Distinct f.ACCESSION_ID) [count],
 f.REQUESTOR_NPI,f.CLIENT_ID,
 datepart(mm,f.RECEIVED_DATE) mm,
datepart(yyyy,f.RECEIVED_DATE)yyyy
from MILLENNIUM_DW_dev..F_ACCESSION_DAILY f

where 
 f.CLIENT_ID not in (select * from SalesDWH..TestPractices)

 and DATEPART(yyyy,f.received_date)=2012
  and DATEPART(mm,f.received_date)=7


group by f.REQUESTOR_NPI,
f.CLIENT_ID,
datepart(mm,f.RECEIVED_DATE),
datepart(yyyy,f.RECEIVED_DATE)
)

select ctebiggie.*,c.* from
ctebiggie
full outer join
ctecount c
on c.REQUESTOR_NPI=ctebiggie.MLISNPI
and c.mm=ctebiggie.[Month]
and c.yyyy=ctebiggie.[Year]
and c.CLIENT_ID=ctebiggie.CLIENT_ID

看这有没有帮助

select distinct main.col1,main.col2  ,
       isnull(( select col3 from table1 where table1.col1=main.col1
       and table1.col2=main.col2 and col3 <>'UNKNOWN'),'UNKNOWN')
from   table1 main

或者你的公平版本会是

SELECT distinct first,
       last,
       cert,
       count,
       npi,
       clientid,
       month,
       year,
      isnull(
      select top 1 dealid from table1 intable where 
      intable.first=maintable.first and
      intable.last=maintable.last and
      intable.cert=maintable.cert and
      intable.npi=maintable.npi and
      intable.clientid=outtable.clientid and
      intable.month=outtable.month and
      intable.year=outtable.year
      where dealid<>'UNKNOWN'),'UNKNOWN') as dealId
FROM  table1 maintable

看这有没有帮助

select distinct main.col1,main.col2  ,
       isnull(( select col3 from table1 where table1.col1=main.col1
       and table1.col2=main.col2 and col3 <>'UNKNOWN'),'UNKNOWN')
from   table1 main

或者你的公平版本会是

SELECT distinct first,
       last,
       cert,
       count,
       npi,
       clientid,
       month,
       year,
      isnull(
      select top 1 dealid from table1 intable where 
      intable.first=maintable.first and
      intable.last=maintable.last and
      intable.cert=maintable.cert and
      intable.npi=maintable.npi and
      intable.clientid=outtable.clientid and
      intable.month=outtable.month and
      intable.year=outtable.year
      where dealid<>'UNKNOWN'),'UNKNOWN') as dealId
FROM  table1 maintable

---

假设您有基本查询，我将在这个结果集上分配行数和按分区函数计数。然后在外部选择，如果计数为1，则选择未知，否则不选择

SELECT first,
       last,
       deaID,
       cert,
       count,
       npi,
       clientid,
       month,
       year
  FROM (
         SELECT first,
                last,
                deaID,
                cert,
                count,
                npi,
                clientid,
                month,
                year,
                ROW_NUMBER() OVER (PARTITION BY
                                     first,last,cert,count,npi,clientid,month,year 
                                    ORDER BY CASE WHEN deaID = 'Unkown' THEN 0 ELSE 1 END,
                                       deaID) AS RowNumberInGroup,
                COUNT() OVER (PARTITION BY first,last,cert,count,npi,clientid,month,year)
                    AS CountPerGroup,
                 SUM(CASE WHEN deaID = 'Unkown' THEN 1 ELSE 0 END) 
                     OVER (PARTITION BY first,last,cert,count,npi,clientid,month,year)
                     AS UnknownCountPerGroup
           FROM BaseQuery
      ) T
 WHERE (T.CountPerGroup = T.UnknownCountPerGroup AND T.RowNumberInGroup = 1) OR T.RowNumberInGroup > T.UnknownCountPerGroup

---

假设您有基本查询，我将在这个结果集上分配行数和按分区函数计数。然后在外部选择，如果计数为1，则选择未知，否则不选择

SELECT first,
       last,
       deaID,
       cert,
       count,
       npi,
       clientid,
       month,
       year
  FROM (
         SELECT first,
                last,
                deaID,
                cert,
                count,
                npi,
                clientid,
                month,
                year,
                ROW_NUMBER() OVER (PARTITION BY
                                     first,last,cert,count,npi,clientid,month,year 
                                    ORDER BY CASE WHEN deaID = 'Unkown' THEN 0 ELSE 1 END,
                                       deaID) AS RowNumberInGroup,
                COUNT() OVER (PARTITION BY first,last,cert,count,npi,clientid,month,year)
                    AS CountPerGroup,
                 SUM(CASE WHEN deaID = 'Unkown' THEN 1 ELSE 0 END) 
                     OVER (PARTITION BY first,last,cert,count,npi,clientid,month,year)
                     AS UnknownCountPerGroup
           FROM BaseQuery
      ) T
 WHERE (T.CountPerGroup = T.UnknownCountPerGroup AND T.RowNumberInGroup = 1) OR T.RowNumberInGroup > T.UnknownCountPerGroup

---

---

我想回答您的问题时，您需要提供查询，或者提供获取此信息的部分。@ShawnMelton非常感谢您指出这一点。我忘了把它包括在内了！！我想回答您的问题时，您需要提供查询，或者提供获取此信息的部分。@ShawnMelton非常感谢您指出这一点。我忘了把它包括在内了！！非常感谢！！你能告诉我你认为tim的查询是否相似吗？请检查更新的查询，它不相似。它将处理各种情况，例如，如果您有重复未知，则只返回单个未知，如果您甚至有一条不未知的记录，则所有未知记录都将被抑制。我已使用您为我提供的内容更新了我的查询：我收到消息102，级别15，状态1，第156行“COUNT”附近的语法不正确。很抱歉，我错过了一个，在RowNumberGroup之后。我现在已经修好了。该查询尚未测试。非常感谢！！你能告诉我你认为tim的查询是否相似吗？请检查更新的查询，它不相似。它将处理各种情况，例如，如果您有重复未知，则只返回单个未知，如果您甚至有一条不未知的记录，则所有未知记录都将被抑制。我已使用您为我提供的内容更新了我的查询：我收到消息102，级别15，状态1，第156行“COUNT”附近的语法不正确。很抱歉，我错过了一个，在RowNumberGroup之后。我现在已经修好了。该查询尚未测试。非常感谢您的帮助。你能告诉我这是如何消除重复的吗？你能解释一下吗？在我的例子中，这一列不包括col3，在你的例子中不包括DEALID，然后对除col3或DEALID之外的所有其他列进行区分，将得到所需的结果，现在通过查询表将该列添加到选择列表中。非常感谢这看起来很神奇。你能告诉我如何将它应用到我的查询中吗？我收到这个错误消息512，16级，状态1，第3行子查询返回了超过1个值。当子查询在=、！=、=或者当子查询用作表达式时。isnull从ctemain中选择IMS\u DEA\u NBR，其中ctemain.IMS\u PROFESSIONAL\u ID\u NBR\u src=main.IMS\u PROFESSIONAL\u ID\u NBR\u src和ctemain.IMS\u CERTIFICATION\u CODE=main.IMS\u CERTIFICATION\u CODE和ctemain.[Month]和ctemain.[Year]=main.[Year]和ctemain.[count]=main.[count]和ctemain.REQUESTOR_NPI=main.REQUESTOR_NPI和ctemain.CLIENT_ID2=main.CLIENT_ID2和ctemain.mm=main.mm和ctemain.yyyy=main.yyyy以及IMS_DEA_NBR'UNKNOWN'，'UNKNOWN'，因为这会返回多次请求，非常感谢您的帮助。你能告诉我这是如何消除重复的吗？你能解释一下吗？在我的例子中，这一列不包括col3，在你的例子中不包括DEALID，然后对除col3或DEALID之外的所有其他列进行区分，将得到所需的结果，现在通过查询表将该列添加到选择列表中。非常感谢这看起来很神奇。你能告诉我如何将它应用到我的查询中吗？我收到这个错误消息512，16级，状态1，第3行子查询返回了超过1个值。当子查询在=、！=、=或者当子查询用作表达式时。isnull从ctemain中选择IMS\u DEA\u NBR，其中ctemain.IMS\u PROFESSIONAL\u ID\u NBR\u src=main.IMS\u PROFESSIONAL\u ID\u NBR\u src和ctemain.IMS\u CERTIFICATION\u CODE=main.IMS\u CERTIFICATION\u CODE和ctemain.[Month]和ctemain.[Year]=main.[Year]和ctemain.[count]=main.[count]和ctemain.REQUESTOR_NPI=main.REQUESTOR_NPI和ctemain.CLIENT_ID2=main.CLIENT_ID2和ctemain.mm=main.mm和ctemain.yyy=main.yy yy和IMS_DEA_NBR“未知”，“未知”，因为它可以返回多个REOCRD