Sql 仅当值等于或大于3500时求和？

下面有3个事务，我只想对值等于或大于3500的事务编号求和：

transaction no.   total
0001              1,000 
0001              2,000 
0001              3,000 
0001              4,000 

0002              2,000 
0002              3,000 

0003              1,000 
0003              1,000 
0003              1,000 

这是我预期的结果：

transaction no.   total
0001              10,000 
0002              5,000 

---

当然，交易编号0003不会显示，因为它低于3500。

使用

group by

和

Having子句

select transactionNo,sum(total) as totalval
from tablename
group by transactionNo
having sum(total)>3500

---

将

分组依据

与

Having子句一起使用

select transactionNo,sum(total) as totalval
from tablename
group by transactionNo
having sum(total)>3500

---

您只需使用having子句，如下所示：

SELECT transactionNo, SUM(total) AS total
FROM myTable
GROUP BY transactionNo
HAVING SUM(total) > 3500

---

您只需使用having子句，如下所示：

SELECT transactionNo, SUM(total) AS total
FROM myTable
GROUP BY transactionNo
HAVING SUM(total) > 3500

HAVING子句已添加到SQL，因为WHERE关键字无法 可以与聚合函数一起使用

HAVING子句已添加到SQL，因为WHERE关键字无法 可以与聚合函数一起使用

---

您可以使用以下代码：

SELECT DISTINCT     transactionNo,
   runningtotal
FROM   (
       SELECT myTable1.transactionNo,
              myTable1.total,
              SUM(myTable2.total) AS runningtotal
       FROM   myTable myTable1
              INNER JOIN myTable myTable2
                   ON  myTable1.transactionNo = myTable2.transactionNo
       GROUP BY
              myTable1.transactionNo,
              myTable1.total
   )            result
WHERE  runningtotal > 3500

或者您可以使用窗口功能和CTE

;WITH ResultTable AS (
      SELECT DISTINCT transactionNo,
             SUM(total) OVER(PARTITION BY transactionNo) AS total
      FROM   myTable
  )

SELECT *
FROM   ResultTable
WHERE  ResultTable.total > 3500

---

您可以使用以下代码：

SELECT DISTINCT     transactionNo,
   runningtotal
FROM   (
       SELECT myTable1.transactionNo,
              myTable1.total,
              SUM(myTable2.total) AS runningtotal
       FROM   myTable myTable1
              INNER JOIN myTable myTable2
                   ON  myTable1.transactionNo = myTable2.transactionNo
       GROUP BY
              myTable1.transactionNo,
              myTable1.total
   )            result
WHERE  runningtotal > 3500

或者您可以使用窗口功能和CTE

;WITH ResultTable AS (
      SELECT DISTINCT transactionNo,
             SUM(total) OVER(PARTITION BY transactionNo) AS total
      FROM   myTable
  )

SELECT *
FROM   ResultTable
WHERE  ResultTable.total > 3500

---

使用“在您的分组之后拥有”

group by[transaction no.]having sum（total）>=3500

使用“在您的分组之后拥有”

group by[transaction no.]having sum（total）>=3500