Sql 请您将重复的结果集（名、姓）加入原始表。当前接受的答案有限，请查看哪一个是正确的实现。（虽然不是我喜欢的技术。）目前被接受的答案是有限的，看看哪一个是正确的实现。（虽然不是我喜欢的技术）这个也很好用。。。基本上选择任何行，在那里你可以找到任何不同ID的副本

---

请您将重复的结果集（名、姓）加入原始表。当前接受的答案有限，请查看哪一个是正确的实现。（虽然不是我喜欢的技术。）目前被接受的答案是有限的，看看哪一个是正确的实现。（虽然不是我喜欢的技术）这个也很好用。。。基本上选择任何行，在那里你可以找到任何不同ID的副本。这一个也很好地工作。。。基本上，选择可以找到具有不同ID的任何副本的任何行。

id | firstname | lastname
---+-----------+----------
1  | alex      | marti
2  | mark      | finger
3  | alex      | marti
4  | ted       | port

1  | alex      | marti
3  | alex      | marti

firstname | lastname
----------+----------
mark      | finger
alex      | marti
ted       | port

Select Id, First_Name, Last_Name
FROM
(
Select Id, First_Name, Last_Name,
Count() Over (Partition By First_Name,Last_Name) Count
From Emp
) AS T
Where T.Count > 1

select a.* from t a,
(select first, last from t group by first, last having count(*) > 1) b
where a.first = b.first and a.last = b.last

select max(id) id, firstname, lastname from t group by firstname, lastname having count(*) > 1

select min(id) minid, max(id) maxid, firstname, lastname from t group by firstname, lastname having count(*) > 1

select id, firstname, lastname
from table t
where exists (select 1
from table t2
where t2.firstname = t.firstname
and t2.lastname = t.lastname
and t2.id <> t.id)

 SELECT COUNT(*) as num, ID, Firstname, Lastname FROM TableA GROUP BY ID, Firstname, Lastname;

INSERT INTO TempTableA(Dups, ID, Firstname, Lastname) SELECT COUNT(*) as num, ID, Firstname, Lastname FROM TableA GROUP BY ID, Firstname, Lastname having count(*)>=1;

DELETE FROM TableA Where ID NOT IN (SELECT t.ID  FROM TempTableA t);

--Remove Duplicate Rows with different ID SQL SERVER

CREATE TABLE #TempTable
(
    Id        int,
    Firstname varchar(20),
    Lastname  varchar(20)
)

INSERT INTO #TempTable( Id, Firstname, Lastname) SELECT min(Id)as Id, Firstname, Lastname 
FROM UserTable 
GROUP BY  Firstname, Lastname

delete from UserTable where Id not in(select Id from #TempTable)

drop #TempTable

SELECT GROUP_CONCAT(DISTINCT id SEPARATOR ',') AS ids, firstname, lastname FROM t GROUP BY firstname, lastname HAVING COUNT(*) > 1

ids | firstname | lastname
----+-----------+----------
1,3 | alex      | marti