Zend：如何将SQL查询与'；比如'；关键词？

我正在使用zend框架。我在zend中使用下面的查询，它对我非常有效

$table = $this->getDbTable();
$select = $table->select();
$select->where('name = ?', 'UserName');
$rows = $table->fetchAll($select);

现在我想在zend中用'like'关键字创建另一个查询。在简单SQL中就是这样

SELECT * FROM Users WHERE name LIKE 'U%'

现在如何为上述查询转换我的zend代码？

试试：

$table = $this->getDbTable();
$select = $table->select();
$select->where('name LIKE ?', 'UserName%');
$rows = $table->fetchAll($select);

或者，如果用户名是一个变量：

$table = $this->getDbTable();
$select = $table->select();
$select->where('name LIKE ?', $userName.'%');
$rows = $table->fetchAll($select);

$user = new Application_Model_DbTable_User();
// User List
$uname=$_POST['uname'];

$query = $user
    ->select()
    ->where('firstname LIKE ?', $uname.'%')
    ->ORwhere('lastname LIKE ?', $_POST['lname'].'%')
    ->ORwhere('emailid LIKE ?', $_POST['email'].'%');

$userlist = $user->fetchAll($query);