sql分组。。。事情

我有以下数据：

ID  Country   City    Type   Qty    SomeDate    SomeDate1    SomeDate2
1   Canada    Ontario Type1  1      01/01/2009  02/02/2009   03/03/2009
2   Canada    Ontario Type2  1      01/01/2009  02/02/2009   03/03/2009
3   Germany   Berlin  Type1  1      03/01/2007  02/01/2008   04/03/2006
4   Germany   Berlin  Type1  3      03/01/2007  02/01/2008   04/03/2006

我需要输出为：

ID  Country   City     Qty    SomeDate    SomeDate1    SomeDate2
1   Canada    Ontario  2      01/01/2009  02/02/2009   03/03/2009
3   Germany   Berlin   4      03/01/2007  02/01/2008   04/03/2006

同一城市之间的日期是相同的

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那么，怎么做呢？

这很简单。你真的应该考虑学习SQL基础知识。你也需要在GROUPBY子句中选择列表中的所有列。@费兹：这是不正确的。您在正在聚合的GROUP BY子句中不包括列。是的，我应该说选择列表中的所有非聚合列。抱歉…ID和Qty不应包含在GROUP BY子句中，因为您正在这些列上进行聚合。

SELECT
    MIN(ID),
    Country,
    City,
    SUM(Qty),
    SomeDate,
    SomeDate1,
    SomeDate2
FROM
    MyTable
GROUP BY
    Country,
    City,
    SomeDate,
    SomeDate1,
    SomeDate2

SELECT MIN(ID), Country, City, SUM(Qty), MIN(SomeDate), MIN(SomeDate1), MIN(SomeDate2)
FROM myTable
GROUP BY Country, City

SELECT MIN(ID) AS ID, Country, City, SUM(Qty) AS Qty, SomeDate, SomeDate1, SomeDate2
FROM Table 
Group BY Country, City, SomeDate, SomeDate1, SomeDate2

SELECT MIN(ID),
    Country,
    City,
    SUM(Qty) AS Qty,
    MIN(SomeDate) AS SomeDate,
    MIN(SomeDate1) AS SomeDate1,
    MIN(SomeDate2) AS SomeDate2
FROM sourceTable
GROUP BY Country, City;