基于使用SQL存储在列中的值，以10秒为间隔添加秒数

我们走吧。说表A

 Time1.       Col
10:10:00.      3
10:10:10.      1
10:10:20.      2

结果

Time1       calculated.     Col

10:10:00    10:10:10       3
10:10:00    10:10:20       3
10:10:00    10:10:30       3
10:10:10    10:10:20       1
10:10:20    10:10:30       2
10:10:20    10:10:40       2

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一个简单的方法使用递归CTE。并非所有数据库都使用递归关键字：

with recursive cte (time1, col, n)
      select time1, col, 1
      from a
      union all
      select time1, col, n + 1
      from cte
      where n < col
     )
select time1, time1 + (n - 1) * interval '10 second' as calculated, col
from cte;

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用您正在使用的数据库标记您的问题。

select a.time1,
       a.time1 + (n.n - 1) * interval '10 second' as calculated,
       a.col
from a join
     (select row_number() over (order by time1) as n
      from a
     ) n
     on n.n <= a.col;