Sql 续集包括Where条件

我在如何查询多个包含where条件方面遇到问题

尝试使用直接查询sql，效果很好。我使用sql制作了一个示例，但在使用sequelize query将其转换为node.js时遇到问题

这是正确的SQL

SELECT pr.id, pr.component_id, pr.requirement_type_id, c.name, rt.name
FROM product_requirements as pr
LEFT JOIN components as c
ON pr.component_id = c.id
LEFT JOIN requirement_types as rt
ON pr.requirement_type_id = rt.id
WHERE c.name LIKE '%Product%'
OR rt.name LIKE '%Product%';

我尝试将其转换为sequelize，这是我到目前为止所做的，但它不断得到错误或正确的结果

let query = {
    where : {
        [Op.or] : [
            {component.name : { [Op.like] : `%${keyword}%` }},
            {requirement.name : { [Op.like] : `%${keyword}%` }}
        ]
    },
    include : [
        {
            model : models.components,
            as : 'component'
        },
        {
            model : models.requirement_types,
            as : 'requirement'
        }
    ]
}

---

我希望它会像sql结果一样

我认为中的查询不理解别名

var where = {
    [Op.or]: [
        sequelize.literal(`[components].name like "%${keyword}%"`),
        sequelize.literal(`[requirement_types].name like "%${keyword}%"`)
    ]
};
var include = [
    {
        model: models.components,
        as: 'component'
    },
    {
        model: models.requirement_types,
        as: 'requirement'
    }
];
product_requirements.findAll({
    where: where,
    include: include

}).then(results => {
});

---

发现我们需要添加

required:false

以使其正常工作并像这样编码

let where = {
    product_id : productId,
    [Op.or] : [
        {"$component.name$" : {[Op.like] : `%${keyword}%`}},
        {"$requirement_type.name$" : {[Op.like] : `%${keyword}%`}}
    ]
}
let include = [
    { model: models.components, required: false },
    { model: models.requirement_types, required: false }
]
query = {
    where : where,
    include : include
}

models.product_requirements.findAll(query)
        .then((result) => {
            res.status(200).send({
                data : result
            })
        })
        .catch((err) => {
            res.error(err)
        })