具有多个计数的Sql pivot

我有以下疑问：

select distinct 
(SELECT  COUNT (TaskID) FROM Task, Employee where SupervisorID = '752A0F4D-9905-4D55-87F1-AFA19245C206' and task.UserID = Employee.UserID) as Total,
(SELECT  COUNT (TaskID) FROM Task, Employee where SupervisorID = '752A0F4D-9905-4D55-87F1-AFA19245C206' and task.UserID = Employee.UserID and DateDue <= DATEADD(day,-1, GETDATE()) )as TotalOverdue,
(SELECT  COUNT (TaskID) FROM Task, Employee where SupervisorID = '752A0F4D-9905-4D55-87F1-AFA19245C206' and task.UserID = Employee.UserID and DateDue >= DATEADD(day,-1, GETDATE()) )  as Totaldue
from Task

但是，我希望它的格式如下：

Total: 5
TotalOverdue: 4
TotalDue: 1

---

我试过使用pivot函数，但不能真正让它正常工作。有什么想法吗？

我想你可以通过条件聚合做你想做的事情：

select count(*) as Total,
       sum(case when DateDue <= DATEADD(day, -1, GETDATE()) then 1 else 0
           end) as TotalOverdue,
       sum(case when DateDue >=  DATEADD(day, -1, GETDATE()) then 1 else 0
           end) as TotalDue
from Task join
     Employee
     on task.UserID = Employee.UserID
where SupervisorID = '752A0F4D-9905-4D55-87F1-AFA19245C206';

选择count（*）作为总计，
求和（DateDue=DATEADD（day，-1，GETDATE（））时的大小写为1，否则为0
(完)到期
从任务加入
雇员
在task.UserID=Employee.UserID上
其中SupervisorID='752A0F4D-9905-4D55-87F1-AFA19245C206'；

如果你想让所有的主管都知道

select SupervisorID, count(*) as Total,
       sum(case when DateDue <= DATEADD(day, -1, GETDATE()) then 1 else 0
           end) as TotalOverdue,
       sum(case when DateDue >=  DATEADD(day, -1, GETDATE()) then 1 else 0
           end) as TotalDue
from Task join
     Employee
     on task.UserID = Employee.UserID;

选择SupervisorID，将（*）计算为总数，
求和（DateDue=DATEADD（day，-1，GETDATE（））时的大小写为1，否则为0
(完)到期
从任务加入
雇员
on task.UserID=Employee.UserID；

编辑：

你真的想取消填充数据。这里有一种方法：

select n.which,
       (case when n.which = 'Total'
             then count(*)
             when n.which = 'TotalOverdue'
             then sum(case when DateDue <= DATEADD(day, -1, GETDATE()) then 1 else 0
                                 end)
             else sum(case when DateDue >=  DATEADD(day, -1, GETDATE()) then 1 else 0
                      end)
        end) as value
from Task join
     Employee
     on task.UserID = Employee.UserID cross join
     (select 'Total' as which union all 'TotalOverdue' union all 'TotalDue') n
group by n.which;

选择n，
（n.which='Total'时的情况）
然后计数（*）
当n.which='total逾期'
然后求和（DateDue=DATEADD（day，-1，GETDATE（））时的大小写为1，否则为0
(完)
结束）作为值
从任务加入
雇员
在task.UserID=Employee.UserID交叉联接上
（选择“Total”作为联合所有“TotalOverside”联合所有“TotalDue”）n
按n.which分组；

---

如果您想要一列是字符串，请使用

concat（）

您正在查找运算符…我尝试使用union all运算符，但结果只是在一列中包含数据，但无法查看哪一行属于哪一列。您的函数工作得很好，但它无法透视数据。它提供与以前相同的输出。

select n.which,
       (case when n.which = 'Total'
             then count(*)
             when n.which = 'TotalOverdue'
             then sum(case when DateDue <= DATEADD(day, -1, GETDATE()) then 1 else 0
                                 end)
             else sum(case when DateDue >=  DATEADD(day, -1, GETDATE()) then 1 else 0
                      end)
        end) as value
from Task join
     Employee
     on task.UserID = Employee.UserID cross join
     (select 'Total' as which union all 'TotalOverdue' union all 'TotalDue') n
group by n.which;