Sql 选择顶部重复记录
我目前有多条记录,但我只需要一条记录。我尝试过交叉应用,但似乎我错过了一些我自己似乎无法理解的东西。相反,我得到了一个完全不同的值,它甚至不在提供的表中的记录中 任何帮助都将不胜感激Sql 选择顶部重复记录,sql,Sql,我目前有多条记录,但我只需要一条记录。我尝试过交叉应用,但似乎我错过了一些我自己似乎无法理解的东西。相反,我得到了一个完全不同的值,它甚至不在提供的表中的记录中 任何帮助都将不胜感激 id subject enrollmentdate roomNum 00045 science 3-3-2016 98 00045 science 3-3-2016 5
id subject enrollmentdate roomNum
00045 science 3-3-2016 98
00045 science 3-3-2016 52
00089 math 7-25-2017 13
00089 math 7-25-2017 56
00123 social studies 3-1-2016 02
00136 gym 5-2-2017 01
00159 math 9-2-2017 96
查询:
select d.id, c.subject, c.Enrollmentdate, ds.roomNum
from #classrooms as c
cross apply
(select top 1 roomNum, subject,Enrollmentdate
from #classrooms
where subject = c.subject
and enrollmentdate = c.enrollmentdate
order by id desc) as ds
结果:
id subject enrollmentdate roomNum
00045 science 3-3-2016 66
00045 science 3-3-2016 66
如果您只需要一个(并且不太关心哪一个),那么下面的内容可能会有所帮助:
select id,
subject,
enrollmentdate,
max(roomnum) max_roomnum
from #classrooms
group by id,
subject,
enrollmentdate;
如果您只需要一个(并且不太关心哪一个),那么下面的内容可能会有所帮助:
select id,
subject,
enrollmentdate,
max(roomnum) max_roomnum
from #classrooms
group by id,
subject,
enrollmentdate;
如果您想要一个特定的,您可以使用带领带的
top
:
select top (1) with ties c.*
from #classrooms c
order by row_number() over (partition by id, subject, enrollmentdate order by roomNum desc);
或者对于一个真正随机的:
select top (1) with ties c.*
from #classrooms c
order by row_number() over (partition by id, subject, enrollmentdate order by newid() desc);
如果您想要一个特定的,您可以使用带领带的
top
:
select top (1) with ties c.*
from #classrooms c
order by row_number() over (partition by id, subject, enrollmentdate order by roomNum desc);
或者对于一个真正随机的:
select top (1) with ties c.*
from #classrooms c
order by row_number() over (partition by id, subject, enrollmentdate order by newid() desc);
您想选择哪一条记录?我们可以根据什么规则找到它?分组类似的行似乎是您所需要的。你能举一个你想分组的行的例子吗?在“相似”比较中,您将包括哪些列?您希望选择哪一条记录?我们可以根据什么规则找到它?分组相似的行似乎是您所需要的。你能举一个你想分组的行的例子吗?在“相似”比较中,您会包括哪些列?