Sql 自动递增字母数字标识

希望我能在这里得到一些帮助。我有以下存储过程，它将通过插入@NAME中的第一个字母来生成字母数字ID。。i、 e.

@name=Test

将产生。T001。但我试图包括前两个aplha。。i、 e，

@name=Test

生成。TE001。我曾尝试更改

@前缀VARCHAR（2）

，以及..

子字符串（@NAME，1,2）

，但当我这样做时。数字不会自动增加

DECLARE @NEWID VARCHAR(5);
DECLARE @PREFIX VARCHAR(1);
SET @PREFIX = UPPER(SUBSTRING(@NAME, 1, 1))
SELECT @NEWID = (@PREFIX + replicate('0', 3 - len(CONVERT(VARCHAR,N.OID + 1))) +       CONVERT(VARCHAR,N.OID + 1)) FROM (
SELECT CASE WHEN MAX(T.TID) IS null then 0 else MAX(T.TID) end as OID FROM (
SELECT SUBSTRING(ID, 1, 1) as PRE_FIX,SUBSTRING(ID, 2, LEN(ID)) as TID FROM Testing
) AS T WHERE T.PRE_FIX = @PREFIX
) AS N

---

我认为这应该奏效：-

DECLARE @NEWID VARCHAR(5);
DECLARE @PREFIX VARCHAR(2);
SET @PREFIX = UPPER(SUBSTRING(@NAME, 1, 2))
SELECT @NEWID = (@PREFIX + replicate('0', 3 - len(CONVERT(VARCHAR,N.OID + 1))) +       CONVERT(VARCHAR,N.OID + 1)) FROM (
SELECT CASE WHEN MAX(T.TID) IS null then 0 else MAX(T.TID) end as OID FROM (
SELECT SUBSTRING(ID, 1, 2) as PRE_FIX,SUBSTRING(ID, 2, LEN(ID)) as TID FROM Testing
) AS T WHERE T.PRE_FIX = @PREFIX
)

试试这个

DECLARE @NEWID VARCHAR(5);
DECLARE @PREFIX VARCHAR(2);
SET @PREFIX = UPPER(SUBSTRING(@NAME, 1, 2))
SELECT @NEWID = (@PREFIX + REPLICATE('0', 3 - LEN(CONVERT(VARCHAR, N.OID + 1))) + CONVERT(VARCHAR,N.OID + 1)) 
FROM (
      SELECT CASE WHEN MAX(T.TID) IS NULL
                  THEN 0
                  ELSE MAX(T.TID) END AS OID 
      FROM (
            SELECT SUBSTRING(ID, 1, 2) AS PRE_FIX, SUBSTRING(ID, 3, LEN(ID)) AS TID 
            FROM Testing
            ) AS T 
      WHERE T.PRE_FIX = @PREFIX
      ) AS N

---

演示

希望您不要将其用作任何内容的主键，因为最终会出现重复值，除非这是一个单用户数据库，或者您正在为整个事务显式锁定表：）