获取具有SQL Server 2008列的最大值的整行

我想在SQLServer2008中执行上述操作。有什么想法吗？

像这样

设置：

declare @MyTable table(Year int, Month int, Day int, Total int)

insert @MyTable
values
    (2005, 9, 23, 12),
    (2005, 9, 26, 5),
    (2005, 9, 24, 1),
    (2005, 9, 15, 28),
    (2005, 9, 21, 1),
    (2005, 9, 13, 1),
    (2005, 10, 31, 5),
    (2005, 11, 18, 115),
    (2005, 11, 20, 1),
    (2005, 11, 11, 1),
    (2005, 11, 19, 1)

查询：

;with cte
as
(
    select *,
        row_number() over(partition by Year, Month order by Total desc) RowNumber
    from @MyTable
)
select Year, Month, Day, Total 
from cte
where RowNumber = 1

输出：

Year        Month       Day         Total
----------- ----------- ----------- -----------
2005        9           15          28
2005        10          31          5
2005        11          18          115

---

您希望如何处理最大值由两天共享的月份？可能重复