Sql 为什么我的查询中的count（不同的签名者id）会导致ORA-00600错误？

这就是错误所在：

CREATE OR REPLACE FORCE VIEW "EXPCPU_SVS"."TEMP_VW_ZZZ_SVS_DATA_IMPORT" ("ACCOUNT_TYPE", "TOTAL_ACCOUNTS", "TOTAL_SIGNATURES", "TOTAL_SIGNCARDS", "TOTAL_GROUPS", "TOTAL_RULES") AS 
SELECT flag_name            AS ACCOUNT_TYPE,
NVL(TOTAL_ACCOUNTS,0)       AS TOTAL_ACCOUNTS,
NVL(TOTAL_SIGNATURES,0)     AS TOTAL_SIGNATURES,
NVL(TOTAL_SIGNCARDS,0)      AS TOTAL_SIGNCARDS,
NVL(TOTAL_GROUPS,0)         AS TOTAL_GROUPS,
NVL(TOTAL_RULES,0)          AS TOTAL_RULES
FROM
(
SELECT flag_name,TOTAL_ACCOUNTS, TOTAL_SIGNATURES,TOTAL_SIGNCARDS,TOTAL_GROUPS,FLAG_VALUE FROM
(
SELECT flag_name,TOTAL_ACCOUNTS, TOTAL_SIGNATURES,TOTAL_SIGNCARDS,FLAG_VALUE FROM 
(
SELECT flag_name,TOTAL_ACCOUNTS,  TOTAL_SIGNATURES,flag_value
FROM 
(
SELECT flag_name,TOTAL_ACCOUNTS,flag_value 
FROM 
(
SELECT count(*)             AS TOTAL_ACCOUNTS ,
A.HISTORY_FLAG              AS a_history_flag
FROM tbl_sign_account a WHERE a.history_flag IN(0,1,2) GROUP BY a.history_flag
)
FULL OUTER JOIN
(
SELECT flag_value,flag_name FROM temp_zz_tbl_flag_mapping
)
ON flag_value=a_history_flag
)
FULL OUTER JOIN 
(
SELECT COUNT(*)             AS TOTAL_SIGNATURES,
b.history_flag              AS b_history_flag
FROM tbl_signatory b
WHERE b.history_flag IN (0,1,2)
GROUP BY b.history_flag
)
ON b_history_flag=flag_value )
FULL OUTER JOIN
(
SELECT count(distinct signatory_id)             AS TOTAL_SIGNCARDS ,
c.history_flag              AS c_history_flag
FROM  tbl_signature_card c
WHERE c.history_flag IN (0,1,2) GROUP BY c.history_flag
)
ON flag_value=c_history_flag
)FULL OUTER JOIN
(
SELECT count(*)             AS TOTAL_GROUPS,
d.history_flag              AS d_history_flag
FROM tbl_sign_group d
WHERE d.history_flag IN (0,1,2) GROUP BY d.history_flag
)
ON flag_value=d_history_flag
) 
FULL OUTER JOIN
(
SELECT count(*)             AS TOTAL_RULES,
e.history_flag              AS e_history_flag
FROM tbl_sign_rule e WHERE e.history_flag IN (0,1,2) GROUP BY e.history_flag
)
ON e_history_flag=flag_value;

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ORA-00600意味着您遇到了一个内部错误，本质上是一个bug。您可以在My Oracle Support上查找错误的详细信息；有一个关于ORA-00600错误的通用文档，搜索参数

kkqcscpopn_Int

将显示各种已知问题-有关摘要，请参阅文档ID 1267257.1。您需要知道确切的版本和补丁级别，以缩小可能性，如果找不到匹配项或怀疑看到的是相同的内容，则需要提出服务请求。正如错误消息所说，报告错误是发生内部错误时的预期操作

有时，可以通过重写或重新设计正在使用的查询来避免隐藏的bug。在这种情况下，您所做的似乎过于复杂了——不确定为什么要添加这么多级别的查询，或者是否真的需要完整的外部联接。如果您想坚持连接到计算计数（而不是，比方说，在选择列表中有子查询），您可以尝试稍微简化一下，看看这是否有助于解析器。首先，假设您在

temp_zz_tbl_flag_mapping

中始终有您正在使用的三个标志值的记录，我认为这大致相同：

ORA-00600: internal error code, arguments: [kkqcscpopn_Int: 0], [], [], [], [], [], [], [], [], [], [], []
00600. 00000 -  "internal error code, arguments: [%s], [%s], [%s], [%s], [%s], [%s], [%s], [%s]"
*Cause:    This is the generic internal error number for Oracle program
           exceptions.  This indicates that a process has encountered an
           exceptional condition.
*Action:   Report as a bug - the first argument is the internal error number

如果该表/视图中可能没有所有的标志值，则可能需要返回到完整的外部联接，但即使如此，删除嵌套的内联视图也可能会有所不同

---

也可能不是；我无法在任何可用的DB版本中产生错误，因此我无法检查这是否可以避免错误。你必须做一些测试和实验。如果您将其简化为对数据和规则有意义的最简单形式，但仍然会出现错误，则必须获得Oracle的帮助。

“Oracle崩溃”？您能详细说明一下错误消息等吗？我只是添加了错误日志，对此表示抱歉。@Ollie我添加了错误日志返回了一个错误-您的查询可能已“崩溃”，但肯定不是Oracle本身……您是否看到了“报告为错误”部分？如果您有权访问我的Oracle支持，您可以进行搜索，查看是否存在已知问题，并可能找到解决方法。（首先请参见注释1267257.1）。当然，您仍然需要访问权限才能提出服务请求。你也可以尝试重写它-看起来它可以大大简化。谢谢@alex做得很好。

CREATE OR REPLACE  VIEW temp_vw_zzz_svs_data_import AS
SELECT z.flag_name           AS account_type,
  NVL(a.total_accounts, 0)   AS total_accounts,
  NVL(b.total_signatures, 0) AS total_signatures,
  NVL(c.total_signcards, 0)  AS total_signcards,
  NVL(d.total_groups, 0)     AS TOTAL_GROUPS,
  NVL(e.total_rules, 0)      AS TOTAL_RULES
FROM temp_zz_tbl_flag_mapping z
LEFT JOIN (
  SELECT history_flag, COUNT(*) AS total_accounts
  FROM tbl_sign_account
  GROUP BY history_flag
) a ON a.history_flag = z.flag_value
LEFT JOIN (
  SELECT history_flag, COUNT(*) AS total_signatures
  FROM tbl_signatory
  GROUP BY history_flag
) b ON b.history_flag = z.flag_value
LEFT JOIN (
  SELECT history_flag, COUNT(DISTINCT signatory_id) AS total_signcards
  FROM tbl_signature_card
  GROUP BY history_flag
) c ON c.history_flag = z.flag_value
LEFT JOIN (
  SELECT history_flag, COUNT(*) AS total_groups
  FROM tbl_sign_group
  GROUP BY history_flag
) d ON d.history_flag = z.flag_value
LEFT JOIN (
  SELECT history_flag, COUNT(*) AS total_rules
  FROM tbl_sign_rule
  GROUP BY history_flag
) e ON e.history_flag = z.flag_value
WHERE z.flag_value in (0,1,2);