基于事务的SQL分析

我有以下SQL表：

一,。项目级表

二,。主项目表

预期结果

根据以上结果，我们将主菜单项表中的所有菜单项按行列出，并根据不同类别检查每个菜单项，以获得售出的总单位

示例：我们正在检查每个订单中与牛肉或鸡肉组1以及其他列oldwithGroup2、SoldwithGroup3一起出售的牛肉项目的数量

---

我们在SoldwithGroup1列下销售了5个单位，因为我们检查了牛肉项目10001，因为同一项目属于同一类别，或者鸡肉与订单号122-1、122-4和122-2匹配

您的问题很难理解，因为这些值在结果集中不会相加

也就是说，对于每一件商品，按组查看同一顺序销售的其他商品的数量是有意义的。我想这就是你想要的

这是一个相当复杂的自连接：

with ilg as (
      select il.*, mi.group
      from itemlevel il join
           materitem mi
           on il.itemno = mi.itemno
     )
select mi.itemno, mi.fullname, mi.MenuCategory,
       sum(case when ilg2.MenuCategory = 'Group1' then ilg2.unitssold end) as group1,
       sum(case when ilg2.MenuCategory = 'Group2' then ilg2.unitssold end) as group2,
       sum(case when ilg2.MenuCategory = 'Group3' then ilg2.unitssold end) as group3
from masteritems mi left join
     ilg
     on mi.itemno = ilg.itemno left join
     ilg ilg2
     on ilg.orderno = ilg2.orderno and ilg.itemno <> ilg2.itemno
group by mi.itemno, mi.fullname, mi.MenuCategory

---

这里有一个方法，首先计算同一订单中每个菜单类别的销售单位

然后根据菜单类别，使用该值对UNITSOLD进行条件求和

SELECT ItemNo, FullName, MenuCategory,
 SUM(CASE WHEN MenuCategory = 'Group1' AND Grp1 > UnitsSold THEN UnitsSold WHEN MenuCategory != 'Group1' AND Grp1 > 0 THEN UnitsSold ELSE 0 END) AS SoldWithGroup1,
 SUM(CASE WHEN MenuCategory = 'Group2' AND Grp2 > UnitsSold THEN UnitsSold WHEN MenuCategory != 'Group2' AND Grp2 > 0 THEN UnitsSold ELSE 0 END) AS SoldWithGroup2,
 SUM(CASE WHEN MenuCategory = 'Group3' AND Grp3 > UnitsSold THEN UnitsSold WHEN MenuCategory != 'Group3' AND Grp3 > 0 THEN UnitsSold ELSE 0 END) AS SoldWithGroup3
FROM
(
    SELECT l.OrderNo, itm.ItemNo, itm.FullName, itm.MenuCategory, l.UnitsSold,
    SUM(CASE WHEN itm.MenuCategory = 'Group1' THEN l.UnitsSold ELSE 0 END) OVER (PARTITION BY l.OrderNo) AS Grp1,
    SUM(CASE WHEN itm.MenuCategory = 'Group2' THEN l.UnitsSold ELSE 0 END) OVER (PARTITION BY l.OrderNo) AS Grp2,
    SUM(CASE WHEN itm.MenuCategory = 'Group3' THEN l.UnitsSold ELSE 0 END) OVER (PARTITION BY l.OrderNo) AS Grp3
    FROM Item itm
    LEFT JOIN ItemLevel l ON l.ItemNo = itm.ItemNo
) q
GROUP BY ItemNo, FullName, MenuCategory
ORDER BY ItemNo;

---

在rextester上进行测试

结果表中的数字似乎与原始数据无关，这使得我们很难理解其中的逻辑。@GordonLinoff我们在SoldwithGroup1列下卖出了5个单位，因为我们检查了牛肉项目10001，因为同一项目属于同一类别，或者鸡肉符合订单122-1，122-4和122-2.在colmun Group 1的产量中，我不想计算Group 1下售出的牛肉数量，而是应该将Group 1的牛肉总量相加

ItemNo    FullName   MenuCategory    SoldwithGroup1     SoldwithGroup2   SoldwithGroup3
-----------------------------------------------------------------------------------------------
10001       Beef      Group1            5                    2                  0
10002       Chicken   Group1            12                   2                  0
10003       Bread     Group2            0                    3                  0                  
10004       Beans     Group2            4                    7                  0
10005       Orange    Group3            0                    0                  0

with ilg as (
      select il.*, mi.group
      from itemlevel il join
           materitem mi
           on il.itemno = mi.itemno
     )
select mi.itemno, mi.fullname, mi.MenuCategory,
       sum(case when ilg2.MenuCategory = 'Group1' then ilg2.unitssold end) as group1,
       sum(case when ilg2.MenuCategory = 'Group2' then ilg2.unitssold end) as group2,
       sum(case when ilg2.MenuCategory = 'Group3' then ilg2.unitssold end) as group3
from masteritems mi left join
     ilg
     on mi.itemno = ilg.itemno left join
     ilg ilg2
     on ilg.orderno = ilg2.orderno and ilg.itemno <> ilg2.itemno
group by mi.itemno, mi.fullname, mi.MenuCategory

SELECT ItemNo, FullName, MenuCategory,
 SUM(CASE WHEN MenuCategory = 'Group1' AND Grp1 > UnitsSold THEN UnitsSold WHEN MenuCategory != 'Group1' AND Grp1 > 0 THEN UnitsSold ELSE 0 END) AS SoldWithGroup1,
 SUM(CASE WHEN MenuCategory = 'Group2' AND Grp2 > UnitsSold THEN UnitsSold WHEN MenuCategory != 'Group2' AND Grp2 > 0 THEN UnitsSold ELSE 0 END) AS SoldWithGroup2,
 SUM(CASE WHEN MenuCategory = 'Group3' AND Grp3 > UnitsSold THEN UnitsSold WHEN MenuCategory != 'Group3' AND Grp3 > 0 THEN UnitsSold ELSE 0 END) AS SoldWithGroup3
FROM
(
    SELECT l.OrderNo, itm.ItemNo, itm.FullName, itm.MenuCategory, l.UnitsSold,
    SUM(CASE WHEN itm.MenuCategory = 'Group1' THEN l.UnitsSold ELSE 0 END) OVER (PARTITION BY l.OrderNo) AS Grp1,
    SUM(CASE WHEN itm.MenuCategory = 'Group2' THEN l.UnitsSold ELSE 0 END) OVER (PARTITION BY l.OrderNo) AS Grp2,
    SUM(CASE WHEN itm.MenuCategory = 'Group3' THEN l.UnitsSold ELSE 0 END) OVER (PARTITION BY l.OrderNo) AS Grp3
    FROM Item itm
    LEFT JOIN ItemLevel l ON l.ItemNo = itm.ItemNo
) q
GROUP BY ItemNo, FullName, MenuCategory
ORDER BY ItemNo;