用于获取JIT spacetree数据的复杂sql查询_Sql_Sql Server_Sql Server 2008

用于获取JIT spacetree数据的复杂sql查询

sql sql-server sql-server-2008

用于获取JIT spacetree数据的复杂sql查询,sql,sql-server,sql-server-2008,Sql,Sql Server,Sql Server 2008,我需要为spacetree构建json字符串，如下所示：- WITH CustomerTree AS ( SELECT ParentID ,CustomerID ,0 AS Level FROM BinaryTree WHERE ParentID = 2 UNION ALL SELECT BinaryTree.ParentID ,BinaryTree.CustomerID ,Cu

我需要为spacetree构建json字符串，如下所示：-

WITH CustomerTree AS (
    SELECT ParentID
          ,CustomerID
          ,0 AS Level
    FROM BinaryTree
    WHERE ParentID = 2
  UNION ALL
    SELECT BinaryTree.ParentID
          ,BinaryTree.CustomerID
          ,CustomerTree.Level + 1 AS Level
    FROM BinaryTree
         INNER JOIN CustomerTree
            ON BinaryTree.ParentID = CustomerTree.CustomerID
)
SELECT CustomerTree.ParentID
      ,CustomerTree.CustomerId
      ,Customers.FirstName
FROM CustomerTree
     INNER JOIN Customers
         ON CustomerTree.CustomerID = Customers.CustomerID

目前我正在使用以下查询：-

SELECT BT.ParentID,BT.CustomerID,CU.firstname 
from BinaryTree BT INNER JOIN Customers CU on BT.CustomerID=CU.CustomerID
WHERE [ParentID] = 2
ORDER BY BT.ParentID,BT.CustomerID

WITH CustomerTree AS (
    SELECT ParentID
          ,CustomerID
          ,0 AS Level
    FROM BinaryTree
    WHERE ParentID = 2
  UNION ALL
    SELECT BinaryTree.ParentID
          ,BinaryTree.CustomerID
          ,CustomerTree.Level + 1 AS Level
    FROM BinaryTree
         INNER JOIN CustomerTree
            ON BinaryTree.ParentID = CustomerTree.CustomerID
)
SELECT CustomerTree.ParentID
      ,CustomerTree.CustomerId
      ,Customers.FirstName
FROM CustomerTree
     INNER JOIN Customers
         ON CustomerTree.CustomerID = Customers.CustomerID

返回的结果如下：-

ParentID   CustomerID  firstname
     2      100176         Bill
     2      115468        will

WITH CustomerTree AS (
    SELECT ParentID
          ,CustomerID
          ,0 AS Level
    FROM BinaryTree
    WHERE ParentID = 2
  UNION ALL
    SELECT BinaryTree.ParentID
          ,BinaryTree.CustomerID
          ,CustomerTree.Level + 1 AS Level
    FROM BinaryTree
         INNER JOIN CustomerTree
            ON BinaryTree.ParentID = CustomerTree.CustomerID
)
SELECT CustomerTree.ParentID
      ,CustomerTree.CustomerId
      ,Customers.FirstName
FROM CustomerTree
     INNER JOIN Customers
         ON CustomerTree.CustomerID = Customers.CustomerID

这里的意思是2是树的根元素，100176115468是子元素。但是这些子节点100176和115468也有一些子节点，这意味着它们是其他一些子节点的根/父节点。表示查询将是：-

SELECT BT.ParentID,BT.CustomerID,CU.firstname 
from BinaryTree BT INNER JOIN Customers CU on BT.CustomerID=CU.CustomerID
WHERE [ParentID] = 100176
ORDER BY BT.ParentID,BT.CustomerID

WITH CustomerTree AS (
    SELECT ParentID
          ,CustomerID
          ,0 AS Level
    FROM BinaryTree
    WHERE ParentID = 2
  UNION ALL
    SELECT BinaryTree.ParentID
          ,BinaryTree.CustomerID
          ,CustomerTree.Level + 1 AS Level
    FROM BinaryTree
         INNER JOIN CustomerTree
            ON BinaryTree.ParentID = CustomerTree.CustomerID
)
SELECT CustomerTree.ParentID
      ,CustomerTree.CustomerId
      ,Customers.FirstName
FROM CustomerTree
     INNER JOIN Customers
         ON CustomerTree.CustomerID = Customers.CustomerID

和100176的结果：-

 ParentID   CustomerID  firstname
   100176    100222       J
   100176    348645       K

WITH CustomerTree AS (
    SELECT ParentID
          ,CustomerID
          ,0 AS Level
    FROM BinaryTree
    WHERE ParentID = 2
  UNION ALL
    SELECT BinaryTree.ParentID
          ,BinaryTree.CustomerID
          ,CustomerTree.Level + 1 AS Level
    FROM BinaryTree
         INNER JOIN CustomerTree
            ON BinaryTree.ParentID = CustomerTree.CustomerID
)
SELECT CustomerTree.ParentID
      ,CustomerTree.CustomerId
      ,Customers.FirstName
FROM CustomerTree
     INNER JOIN Customers
         ON CustomerTree.CustomerID = Customers.CustomerID

及

WITH CustomerTree AS (
    SELECT ParentID
          ,CustomerID
          ,0 AS Level
    FROM BinaryTree
    WHERE ParentID = 2
  UNION ALL
    SELECT BinaryTree.ParentID
          ,BinaryTree.CustomerID
          ,CustomerTree.Level + 1 AS Level
    FROM BinaryTree
         INNER JOIN CustomerTree
            ON BinaryTree.ParentID = CustomerTree.CustomerID
)
SELECT CustomerTree.ParentID
      ,CustomerTree.CustomerId
      ,Customers.FirstName
FROM CustomerTree
     INNER JOIN Customers
         ON CustomerTree.CustomerID = Customers.CustomerID

结果为115468：-

 ParentID   CustomerID  firstname
  115468     154756       D
  115468     348480       L

WITH CustomerTree AS (
    SELECT ParentID
          ,CustomerID
          ,0 AS Level
    FROM BinaryTree
    WHERE ParentID = 2
  UNION ALL
    SELECT BinaryTree.ParentID
          ,BinaryTree.CustomerID
          ,CustomerTree.Level + 1 AS Level
    FROM BinaryTree
         INNER JOIN CustomerTree
            ON BinaryTree.ParentID = CustomerTree.CustomerID
)
SELECT CustomerTree.ParentID
      ,CustomerTree.CustomerId
      ,Customers.FirstName
FROM CustomerTree
     INNER JOIN Customers
         ON CustomerTree.CustomerID = Customers.CustomerID

但我需要一个查询中的所有家长和孩子，如：-

 ParentID   CustomerID  firstname
    2        100176       Bill
    2        115468       will
  100176     100222       J
  100176     348645       K
  115468     154756       D
  115468     348480       L

WITH CustomerTree AS (
    SELECT ParentID
          ,CustomerID
          ,0 AS Level
    FROM BinaryTree
    WHERE ParentID = 2
  UNION ALL
    SELECT BinaryTree.ParentID
          ,BinaryTree.CustomerID
          ,CustomerTree.Level + 1 AS Level
    FROM BinaryTree
         INNER JOIN CustomerTree
            ON BinaryTree.ParentID = CustomerTree.CustomerID
)
SELECT CustomerTree.ParentID
      ,CustomerTree.CustomerId
      ,Customers.FirstName
FROM CustomerTree
     INNER JOIN Customers
         ON CustomerTree.CustomerID = Customers.CustomerID

100176和115468的子节点也可以有子节点，因此这些子节点也应该是上述结果中100222348645的结果

WITH CustomerTree AS (
    SELECT ParentID
          ,CustomerID
          ,0 AS Level
    FROM BinaryTree
    WHERE ParentID = 2
  UNION ALL
    SELECT BinaryTree.ParentID
          ,BinaryTree.CustomerID
          ,CustomerTree.Level + 1 AS Level
    FROM BinaryTree
         INNER JOIN CustomerTree
            ON BinaryTree.ParentID = CustomerTree.CustomerID
)
SELECT CustomerTree.ParentID
      ,CustomerTree.CustomerId
      ,Customers.FirstName
FROM CustomerTree
     INNER JOIN Customers
         ON CustomerTree.CustomerID = Customers.CustomerID

有人能帮我吗

WITH CustomerTree AS (
    SELECT ParentID
          ,CustomerID
          ,0 AS Level
    FROM BinaryTree
    WHERE ParentID = 2
  UNION ALL
    SELECT BinaryTree.ParentID
          ,BinaryTree.CustomerID
          ,CustomerTree.Level + 1 AS Level
    FROM BinaryTree
         INNER JOIN CustomerTree
            ON BinaryTree.ParentID = CustomerTree.CustomerID
)
SELECT CustomerTree.ParentID
      ,CustomerTree.CustomerId
      ,Customers.FirstName
FROM CustomerTree
     INNER JOIN Customers
         ON CustomerTree.CustomerID = Customers.CustomerID

提前谢谢

WITH CustomerTree AS (
    SELECT ParentID
          ,CustomerID
          ,0 AS Level
    FROM BinaryTree
    WHERE ParentID = 2
  UNION ALL
    SELECT BinaryTree.ParentID
          ,BinaryTree.CustomerID
          ,CustomerTree.Level + 1 AS Level
    FROM BinaryTree
         INNER JOIN CustomerTree
            ON BinaryTree.ParentID = CustomerTree.CustomerID
)
SELECT CustomerTree.ParentID
      ,CustomerTree.CustomerId
      ,Customers.FirstName
FROM CustomerTree
     INNER JOIN Customers
         ON CustomerTree.CustomerID = Customers.CustomerID