如何在SQL视图中将计数组和总和表示为列?
基本上,我在Postgresql中定义了mytable如何在SQL视图中将计数组和总和表示为列?,sql,postgresql,pivot,Sql,Postgresql,Pivot,基本上,我在Postgresql中定义了mytable id integer, ownername text, length integer, status integer 预期的结果是为每个ownername行创建一个具有以下列的视图 ownername | count_in_status1 | sum_length_status1 | count_in_status2 | sum_length_status2 | count_in_status3 | sum_length_status
id integer,
ownername text,
length integer,
status integer
预期的结果是为每个ownername行创建一个具有以下列的视图
ownername | count_in_status1 | sum_length_status1 | count_in_status2 | sum_length_status2 | count_in_status3 | sum_length_status3 | ..... | total_count | total_sum_length
这有点难以解释,但基本上我需要一个计数和每个拥有者的总和,最后是一个总计数和长度的总和。目前实际上有5种状态
试过下面的
create view myview as
select ownername, status, count(*), sum(length) from mytable group by ownername, status
这将返回数据,但不是以我上面介绍的最有效的方式返回。如何实现它?我想这就是你想要的:
create view myview as
select ownername,
count(*) filter (where status = 1) as cnt_status_1,
sum(length) filter (where status = 1) as len_status_1,
count(*) filter (where status = 2) as cnt_status_2,
sum(length) filter (where status = 2) as len_status_2,
. . . -- continue for each status
count(*) as cnt,
sum(length) as length
from mytable
group by ownername;
使用
过滤器
是一个优雅的解决方案(请参见@Gordon Linoff响应)
Te与许多数据库更兼容,yan还可以写:
create view myview as
select ownername,
sum(case when status = 1 then 1 else 0 end) as cnt_status_1,
sum(case when status = 1 then length else 0 end) as len_status_1,
sum(case when status = 1 then 1 else 0 end) as cnt_status_2,
sum(case when status = 1 then length else 0 end) as len_status_2,
. . . -- continue for each status
count(*) as cnt,
sum(length) as length
from mytable
group by ownername;
您不需要状态栏。@没有名字的马。谢谢。事实上,
filter()
是标准的ISO SQL