SQL查询及其对立面的总和和总计数不匹配

以下两个查询的总和产生42 081：

问题1：

SELECT COUNT(DISTINCT SIREN) AS new_column FROM CDEdelux
WHERE Email IS NOT NULL
AND Email <> ""
AND Email <> " "
AND Email <> ''
AND Email <> ' '
AND Email LIKE "%@%.%"
AND Email NOT LIKE "_@%.%"
AND Email NOT LIKE "%bpi%"
AND Email NOT LIKE "%BPI%"
AND Email NOT LIKE "%inconnu%"
AND Email NOT LIKE "%tempo%"
AND Email NOT LIKE "%attente%"
AND Email NOT LIKE "%xx%"
AND Email NOT LIKE "%nsp%"
AND Email NOT LIKE "%contact%"
AND Email NOT LIKE "%info%"
AND Email NOT LIKE "%recuperer%"

查询2对方查询：

SELECT COUNT(DISTINCT SIREN) AS new_column FROM CDEdelux
WHERE Email IS NOT NULL
AND Email <> ""
AND Email <> " "
AND Email <> ''
AND Email <> ' '
AND (Email NOT LIKE "%@%.%"
OR Email LIKE "_@%.%"
OR Email LIKE "%bpi%"
OR Email LIKE "%BPI%"
OR Email LIKE "%inconnu%"
OR Email LIKE "%tempo%"
OR Email LIKE "%attente%"
OR Email LIKE "%xx%"
OR Email LIKE "%nsp%"
OR Email LIKE "%contact%"
OR Email LIKE "%info%"
OR Email LIKE "%recuperer%")

然而，由于它们应该是相反的和互补的，它们应该给我39206，这是该查询的结果：

查询3总计查询：

SELECT COUNT(DISTINCT SIREN) AS new_column FROM CDEdelux
WHERE Email IS NOT NULL
AND Email <> ""
AND Email <> " "
AND Email <> ''
AND Email <> ' '

为什么第一个数字比第二个数字高？

很明显，一个给定的警报可能有多封符合任何一组条件的电子邮件。您可以通过执行以下操作查看重复的电子邮件：

select distinct siren, email
from CDEdelux d1
where exists (select 1 from CDEdelux d2 where d2.siren = d.siren and d2.email <> d.email);

如果你计算了不同的电子邮件，那么数字应该加起来。

警报器可以有多封电子邮件吗？