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Access SQL条件查询_Sql_Ms Access - Fatal编程技术网

Access SQL条件查询

Access SQL条件查询,sql,ms-access,Sql,Ms Access,我试图根据一列的内容检索数据 样本表 Description EID Basecode ----------- ---- --------- ssdad 1001 S2378797 gfd 1002 S1164478 gfdsffsdf 1003 R1165778 ssdad

我试图根据一列的内容检索数据

样本表

  Description    EID        Basecode        
   -----------    ----       ---------    
  ssdad          1001       S2378797     
  gfd            1002       S1164478     
  gfdsffsdf      1003       R1165778     
  ssdad          1004       M0007867     
  gfd            1005       N7765111     
  gfdsffsdf      1006       W5464111     
  gfd            1005       N7765111     
  gfdsffsdf      1006       A4000011 
  gfdsffsdf      1006       W5464111     
  ssdad          1001       2378797     
  gfd            1002       1164478  
  ssdad          1001       965000
  gfd            1002       780000
  yjgk           4456       540000
  kjhkh          2009       150000
  ddd            1004       1040
  d88jg          1004       14C676
   fsa           6565       158 
   fdh           1004       2Khlm
   ggdg          2009       967
如果列数据以字母开头,那么我需要qr1的结果;如果它包含以967854和length>6开头的数字,则得到qry2结果

如何检索除按qry1、qry2排序之外的数据


如何在MS Access中有条件地执行此操作?

您必须执行基本上类似于以下内容的IIF语句

ColValue: IIf((Len([col1])>6 And (Left([col1],2)="12" Or Left([col1],2)="13")),1,0)

ColValue: IIf(Left([col1],1) In ("a","b","c"),1,0)
(注意:一直添加到z)


如果它们满足您的条件,则为1,否则为0。

如果它们不满足这两个条件中的任何一个,该怎么办?我将返回NULL,但您将其更改为所需:

SELECT IIF((LEN([col1])>6 AND (LEFT([col1], 2) = "12" OR LEFT([col1], 2)="13")), qry2,
       IIF(ASC(UCASE(LEFT([col1], 1))) BETWEEN 65 AND 90, qry1, NULL))
FROM myTable