Sql 显示计数最少的数据

我想显示度假村的详细信息，如度假村名称和拥有最少卧室数量的城镇名称。我试过这段代码-

select r.resortname, r.townname
from resort r, cabin c 
where r.resortid = c.resortid
and c.bedroomcount = (select min(sum(c1.bedroomcount)) from cabin c1 group by c1.resortid)
order by r.resortname; 

但是这段代码没有返回任何输出或错误。 请帮忙，提前谢谢！：

我找到了正确的答案-

select r.resortname, r.townname
from resort r, cabin c
where r.resortid = c.resortid
and c.bedroomcount = (select min(min(bedroomcount)) from cabin c1 group by c1.bedroomcount)
order by r.resortname;

---

谢谢你的帮助

使用窗口函数。并加入：

---

要显示度假村，请从resorts表中选择。您想要的是卧室数量最少的，所以应用适当的where子句

select resortname, townname
from resort
where resortid in
(
  select resortid
  from cabin
  group by resortid
  order by sum(bedroomcount)
  fetch first row with ties
);

---

FETCH FIRST子句从Oracle 12c开始可用。

此代码与下面的代码类似，从度假区r选择r.RETRESTNAME，r.townname在r.RETRESTID=c.RETRESTID上加入CAB c，其中c.bedroomcount在select minbedroomcount中按c1从CAB c1组按c1.RETRESTID按r.RETRESTID顺序按r.RETRESTNAME；它输出所有度假村名称，但只应输出一个值最小的度假村名称。@yaminir。r.bedroomcount=c.min_bedroomcount应该只选择最小卧室数。r表中没有卧室数，它只存在于c表中。所以它显示了一个错误。@yaminir。这是有道理的。我修正了答案。

select resortname, townname
from resort
where resortid in
(
  select resortid
  from cabin
  group by resortid
  order by sum(bedroomcount)
  fetch first row with ties
);