SQL错误：正在执行操作

我需要编写一个sql脚本，它必须显示所有man客户机，其最大收入是最低收入的两倍

SELECT
  DISTINCT
  customer_rk,
  max(monthly_income_amt),
  min(monthly_income_amt),
  max(monthly_income_amt) / min(monthly_income_amt) AS income_ratio
FROM asql.individual_customer
WHERE middle_nm LIKE '%ВИЧ'
GROUP BY customer_rk
HAVING income_ratio > 2;

middle_nm，如“%bбЧ”

-用于按中间名对男性进行排序（俄语要求）

以下是表格的外观：

A收到此类错误：

错误：“收入比率”列不存在（第6行）

---

我做错了什么？

而不是

收入比率

写在have子句中为

max（monthly\u income\u amt）/min（monthly\u income\u amt）>2

---

另外，当您分组时，

distinct

没有意义。

而不是

收入比率

将have子句写为

max（monthly\u income\u amt）/min（monthly\u income\u amt）>2

---

另外，

distinct

在分组时没有意义。

需要修改having子句，如下所示

SELECT
      DISTINCT
      customer_rk,
      max(monthly_income_amt),
      min(monthly_income_amt),
      max(monthly_income_amt) / min(monthly_income_amt) AS income_ratio
    FROM asql.individual_customer
    WHERE middle_nm LIKE '%ВИЧ'
    GROUP BY customer_rk
    HAVING (max(monthly_income_amt) / min(monthly_income_amt)) > 2

---

您的having条款需要修改如下

SELECT
      DISTINCT
      customer_rk,
      max(monthly_income_amt),
      min(monthly_income_amt),
      max(monthly_income_amt) / min(monthly_income_amt) AS income_ratio
    FROM asql.individual_customer
    WHERE middle_nm LIKE '%ВИЧ'
    GROUP BY customer_rk
    HAVING (max(monthly_income_amt) / min(monthly_income_amt)) > 2

---

将查询包装到派生表中。然后，您可以在WHERE子句中输入收入比率：

select * from
(
    SELECT
      customer_rk,
      max(monthly_income_amt),
      min(monthly_income_amt),
      max(monthly_income_amt) / min(monthly_income_amt) AS income_ratio
    FROM asql.individual_customer
    WHERE middle_nm LIKE '%ВИЧ'
    GROUP BY customer_rk
) dt
where income__ratio > 2;

---

将查询包装到派生表中。然后，您可以在WHERE子句中输入收入比率：

select * from
(
    SELECT
      customer_rk,
      max(monthly_income_amt),
      min(monthly_income_amt),
      max(monthly_income_amt) / min(monthly_income_amt) AS income_ratio
    FROM asql.individual_customer
    WHERE middle_nm LIKE '%ВИЧ'
    GROUP BY customer_rk
) dt
where income__ratio > 2;

---

为什么选择DISTINCT？GROUP BY不返回重复项。为什么选择DISTINCT？GROUP BY不返回重复项。