Swift 3-将用户输入与字典值匹配

我的应用程序的用户将接受英语测试。他们将通过在单词旁边打勾从列表中选择不同的单词。他们只想选择属于名词的单词。例如，如果他们正确地从10个选项中选择了5个，我如何向他们显示50%的分数。我认为我需要根据用户的输入过滤字典值。用户的输入是一个数组。编写此代码的最佳方法是什么

尝试以下代码：--100%工作

     let myDictionary : [String : Any] =
        [  "Nouns":["One","Two","Three","Four","Five","Six","Seven","Eight","Nine","Ten"],
"Verbs":["Eat","play","dance","walk","run","sing","read","write","go","come"]]
    var myUserSelectedArray:[String] = ["One","come","Three","go","Five","x","Six","x","x","Ten"];

    let myNounArray = myDictionary["Nouns"] as? [String];
    let myVerbArray = myDictionary["Verbs"] as? [String];
    let set1:Set<String> = Set(myUserSelectedArray);
    let set2:Set<String> = Set(myNounArray!);
    let set3:Set<String> = Set(myVerbArray!);
    let scroeInNoun = set1.intersection(set2).count;
    let scroeInVerb = set1.intersection(set3).count;
    print ("score in Verb \((scroeInVerb * 100)/set2.count) %")
    print ("score in noun \((scroeInNoun * 10)/set3.count ) %")
    let finalScore = (scroeInNoun + scroeInVerb) * 100 / ((myNounArray?.count)! + (myVerbArray?.count)!)
    print ("final score in noun \(finalScore) %") 

let myDictionary:[字符串：任意]=
[“名词”：[“一”、“二”、“三”、“四”、“五”、“六”、“七”、“八”、“九”、“十”]，
“动词”：[“吃”、“玩”、“跳舞”、“走”、“跑”、“唱”、“读”、“写”、“去”、“来”]]
var myUserSelectedArray:[字符串]=[“一”、“来”、“三”、“去”、“五”、“x”、“六”、“x”、“x”、“十”]；
让MyNonOnArray=myDictionary[“nomes”]as？[字符串]；
让myVerbArray=myDictionary[“动词”]作为？[字符串]；
让set1:Set=Set（myUserSelectedArray）；
设set2:Set=Set（myNounArray！）；
让set3:Set=Set（myVerbArray！）；
设scroeInNoun=set1.intersection（set2.count）；
设scroeInVerb=set1.交点（set3）.计数；
打印（“动词\（scroeInVerb*100）/set2.count中的分数%”）
打印（“名词分数\（（scroinnoun*10）/set3.count）%”）
设finalScore=（scroeInNoun+scroeInVerb）*100/（（MyNonuArray？.count）！+（myVerbArray？.count）！）
打印（“名词\（最终分数）%”的最终分数）

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如果对您有用，请使用简单的数学公式（正确答案*100）/共问问题接受答案

yes