Swift 如何使用Alamofire(post)上传图片?
我必须发出一个API请求才能上传一张照片,这张照片是由相机拍摄的还是从画廊中挑选的。API中设置的方法已设置,在主体/参数中只有Swift 如何使用Alamofire(post)上传图片?,swift,xcode,upload,alamofire,Swift,Xcode,Upload,Alamofire,我必须发出一个API请求才能上传一张照片,这张照片是由相机拍摄的还是从画廊中挑选的。API中设置的方法已设置,在主体/参数中只有 key:file value: // 其中值是图片本身。(在《邮递员》中,我只是从我的文件上传了一张图片,它就工作了),然后它返回一个包含其他信息的URL。 问题是我无法获得成功响应的请求,并且我不知道如何将UIImage传递给Alamofire。 这就是我所做的 Alamofire.request(baseUrl, method: .post
key:file
value: //
其中值是图片本身。(在《邮递员》中,我只是从我的文件上传了一张图片,它就工作了),然后它返回一个包含其他信息的URL。
问题是我无法获得成功响应的请求,并且我不知道如何将UIImage传递给Alamofire。
这就是我所做的
Alamofire.request(baseUrl,
method: .post,
parameters: ["file" : expenseImage])
.responseJSON(completionHandler: { response in
guard response.result.error == nil else {
print("Error subiendo la imagen \n\(response.result.error!)")
return
}
guard let json = response.result.value as? [String: Any] else {
if let error = response.result.error {
print("Error: \(error.localizedDescription)")
}
return
}
do {
let decoder = JSONDecoder()
let rawData = try JSONSerialization.data(withJSONObject: json, options: [])
let dataObject = try decoder.decode(PutObjectFile.self, from: rawData)
finished(dataObject)
print(dataObject)
print(dataObject.msg.file_info.url)
} catch let error {
print("Error decoding:\n\(error)")
}
})
我在控制台中遇到的错误如下:
responseSerializationFailed(reason: Alamofire.AFError
.ResponseSerializationFailureReason.inputDataNilOrZeroLength)
我尝试使用随机图片url,但也不起作用使用Alamofire的上载方法在
multipartFormData中上载图像。我已经为您更新了代码。使用下面的代码
Alamofire.upload(multipartFormData: { multipartFormData in
multipartFormData.append(expenseImage, withName: "file",fileName: "file.jpg", mimeType: "image/jpg")
},
with: baseUrl)
{ (result) in
switch result {
case .success(let upload, _, _):
upload.uploadProgress(closure: { (progress) in
print("Upload Progress: \(progress.fractionCompleted)")
})
upload.responseJSON { response in
print(response.result.value)
}
case .failure(let encodingError):
print(encodingError)
}
}
您可以使用多部分数据上传图像,请使用以下代码:
let manager = Alamofire.SessionManager.default
do{
manager.upload(multipartFormData: { (formData) in
if let fileData = fileData { // File data
formData.append(fileData, withName: "FILE_NAME", fileName: "simple.jpeg", mimeType: "image/jpeg")
}
}, to: "API_PATH", method: HTTPMethod.post, headers: nil, encodingCompletion: { encoding in
switch encoding{
case .success(let req, _, _):
req.uploadProgress(closure: { (prog) in
progress?(prog)
}).responseJSON { (resObj) in
switch resObj.result{
case .success:
if let resData = resObj.data{
do {
let res = try JSONSerialization.jsonObject(with: resData)
print(res) // Success
} catch let err{
print(err)
}
}
break
case .failure(let err):
print(err)
break
}
}
break
case .failure(let err):
print(err)
break
}
})
}catch let err{
print(err)
}
我也遇到了同样的问题,我通过以下方式解决了它:
阿拉莫菲尔5.0.0-beta.5
AF.upload(multipartFormData: { multipartFormData in
multipartFormData.append(imgData, withName: "file",fileName: "file.jpg", mimeType: "image/jpg")
},
to: url).responseJSON
{ response in print(response)
if let status = response.response?.statusCode {
print(status)
}
//to get JSON return value
if let result = response.value {
let res = result as! [String: String]
let newUrl:String = res["url"]!
print(newUrl)
}
}
我遇到此错误无法使用类型为“((CGFloat)->Data?,with name:String,fileName:String,mimeType:String)”的参数列表调用“append”
您需要将UIImage转换为数据,以便在formData中追加。你这样做了吗?现在我这样做了,我再次遇到这个错误responseSerializationFailed(原因:Alamofire.AFError.responseSerializationFaileureReason.inputDataNilOrZeroLength)
它也不起作用:(表达式类型'()”在没有更多上下文的情况下是不明确的
AF.upload(multipartFormData: { multipartFormData in
multipartFormData.append(imgData, withName: "file",fileName: "file.jpg", mimeType: "image/jpg")
},
to: url).responseJSON
{ response in print(response)
if let status = response.response?.statusCode {
print(status)
}
//to get JSON return value
if let result = response.value {
let res = result as! [String: String]
let newUrl:String = res["url"]!
print(newUrl)
}
}