Swift 筛选器正在返回具有匹配子级的父级的所有子级
我使用的是Swift领域,我的结构如下:Swift 筛选器正在返回具有匹配子级的父级的所有子级,swift,realm,filtering,nspredicate,Swift,Realm,Filtering,Nspredicate,我使用的是Swift领域,我的结构如下: class Navigation: Object { dynamic var key = 0 dynamic var title: String? let companies = List<Companies>() override static func primaryKey() -> String? { return "key" } } class Companies:
class Navigation: Object {
dynamic var key = 0
dynamic var title: String?
let companies = List<Companies>()
override static func primaryKey() -> String? {
return "key"
}
}
class Companies: Object {
dynamic var key = 0
dynamic var name: String?
let locations = List<Locations>()
override static func primaryKey() -> String? {
return "key"
}
}
class Locations: Object {
dynamic var key = 0
...
dynamic var zip: String?
let contacts = List<Contacts>()
override static func primaryKey() -> String? {
return "key"
}
}
class Contacts: Object {
dynamic var key = 0
dynamic var firstName: String?
dynamic var lastName: String?
...
override static func primaryKey() -> String? {
return "key"
}
}
key=4
位是因为过滤器只应在一个特定类别下的公司中搜索
我遇到的问题是,它返回具有匹配位置的公司的所有位置。因此,如果我要查找的邮政编码是12345,并且companyA有一个匹配的位置,则返回companyA下的所有位置,即使它们不匹配
我如何将结果限制为只有匹配的位置
我如何将结果限制为只有匹配的位置
现在,您正在返回一个结果
,但似乎您需要位置。通过向公司
和位置
模型添加一些反向关系属性,我完成了我认为您要查找的内容,然后查询了位置
匹配的zip=='12345'&任意parentcompanys.parentNavigation.key==4
下面是一个示例应用程序,演示了这一点:
import UIKit
import RealmSwift
class Navigation: Object {
dynamic var key = 0
dynamic var title: String?
let companies = List<Companies>()
override static func primaryKey() -> String? {
return "key"
}
}
class Companies: Object {
dynamic var key = 0
dynamic var name: String?
let locations = List<Locations>()
let parentNavigation = LinkingObjects(fromType: Navigation.self, property: "companies")
override static func primaryKey() -> String? {
return "key"
}
}
class Locations: Object {
dynamic var key = 0
// ...
dynamic var zip: String?
let contacts = List<Contacts>()
let parentCompanies = LinkingObjects(fromType: Companies.self, property: "locations")
override static func primaryKey() -> String? {
return "key"
}
}
class Contacts: Object {
dynamic var key = 0
dynamic var firstName: String?
dynamic var lastName: String?
// ...
override static func primaryKey() -> String? {
return "key"
}
}
@UIApplicationMain
class AppDelegate: UIResponder, UIApplicationDelegate {
var window: UIWindow?
func application(_ application: UIApplication, didFinishLaunchingWithOptions launchOptions: [UIApplicationLaunchOptionsKey: Any]?) -> Bool {
_ = try? FileManager.default.removeItem(at: Realm.Configuration.defaultConfiguration.fileURL!)
let realm = try! Realm()
// Objects Matching Query
try! realm.write {
// Locations
let locations = Locations()
locations.zip = "12345"
// Companies
let companies = Companies()
companies.name = "Companies A"
companies.locations.append(locations)
// Nav
let nav = Navigation()
nav.key = 4
nav.companies.append(companies)
// Add to Realm
realm.add(nav)
}
let locationsIn12345AndNavigationKey4 = realm.objects(Locations.self)
.filter("zip == '12345' && ANY parentCompanies.parentNavigation.key == 4")
print(locationsIn12345AndNavigationKey4)
return true
}
}
导入UIKit
导入RealmSwift
类导航:对象{
动态变量键=0
动态变量标题:字符串?
让公司=列表()
重写静态func primaryKey()->字符串{
返回“键”
}
}
类别公司:对象{
动态变量键=0
动态变量名:字符串?
让位置=列表()
让parentNavigation=LinkingObjects(fromType:Navigation.self,属性:“companys”)
重写静态func primaryKey()->字符串{
返回“键”
}
}
类位置:对象{
动态变量键=0
// ...
动态var-zip:String?
让联系人=列表()
让parentcompanys=LinkingObjects(fromType:companys.self,property:“locations”)
重写静态func primaryKey()->字符串{
返回“键”
}
}
类联系人:对象{
动态变量键=0
动态变量名:字符串?
动态变量lastName:String?
// ...
重写静态func primaryKey()->字符串{
返回“键”
}
}
@UIApplicationMain
类AppDelegate:UIResponder、UIApplicationLegate{
变量窗口:UIWindow?
func应用程序(application:UIApplication,didFinishLaunchingWithOptions launchOptions:[UIApplicationLaunchOptions:[UIApplicationLaunchOptions:任何]?)->Bool{
_=try?FileManager.default.removietem(位于:Realm.Configuration.defaultConfiguration.fileURL!)
让realm=try!realm()
//对象匹配查询
试试看!写吧{
//地点
让位置=位置()
locations.zip=“12345”
//公司
让公司=公司()
companys.name=“公司A”
公司.地点.附加(地点)
//导航
设nav=Navigation()
导航键=4
资产净值公司追加(公司)
//添加到领域
realm.add(导航)
}
让Locationsin12345和NavigationKey4=realm.objects(Locations.self)
.filter(“zip='12345'和&anyparentcompanys.parentNavigation.key==4”)
打印(位置SIN12345和导航键4)
返回真值
}
}
这张照片是:
Results<Locations> (
[0] Locations {
key = 0;
zip = 12345;
contacts = RLMArray <0x6000000f2100> (
);
}
)
结果(
[0]位置{
键=0;
zip=12345;
联系人=玛丽(
);
}
)
我可以使用它,但理想情况下,我希望它也有“拥有”这些位置的公司,这样用户就知道他们在找什么公司。有很多地方的名称类似,比如“主办公室”。简单:locationsin12345和navigationkey4.flatMap{$0.parentcompanys}
你能让这个代码更友好吗?这应该是进入过滤器的字符串吗?这些是实际的函数调用吗?我想这也必须通过反向关系来完成?我不明白这些问题中的任何一个。请您重新措辞好吗?您的评论,Locationsin12345和NavigationKey4.flatMap{$0.ParentCompanys}
,这应该作为字符串进入filter()
函数,还是作为代码?如果是,我应该将其附加到什么?
Results<Locations> (
[0] Locations {
key = 0;
zip = 12345;
contacts = RLMArray <0x6000000f2100> (
);
}
)