如何在swift中过滤UITableView中的多个字段

我在字符串数组中有国家代码和国家名称。我刚刚过滤了国家名称并显示在过滤后的表格视图中。但是，在显示时，我无法从原始tableview中获取相应的国家/地区代码。国家代码未被过滤。请帮帮我。如何筛选tableView单元格中的多个字段

我的代码：

var countries = [String]()
for countryCodes : AnyObject in NSLocale.ISOCountryCodes() {
    let dictionary : NSDictionary = NSDictionary(object:countryCodes, forKey:NSLocaleCountryCode)
    let identifier : NSString? = NSLocale.localeIdentifierFromComponents(dictionary)
    if ((identifier) != nil) {
        let country : NSString = NSLocale.currentLocale().displayNameForKey(NSLocaleIdentifier, value: identifier!)!
        countries.append(country)
        println(countries)
    }
}
println(countries)
var country_codes = [String]()
country_codes =  NSLocale.ISOCountryCodes() as [String]
println(country_codes) //Working Successfully.

//SEARCH BAR WHILE TYPING TEXT
func searchBar(searchBar: UISearchBar, textDidChange searchText: String) {

        if(countElements(searchBar.text) >= 3)
        {
            searchActive = true

            filtered = countries.filter({ (text) -> Bool in
                let tmp: NSString = text
                let range = tmp.rangeOfString(searchText, options: NSStringCompareOptions.CaseInsensitiveSearch)
                return range.location != NSNotFound
            })
//I filtered only one fields. So, Filtered results are working fine, but, I am having one more fields in tableview cell. That is displaying different datas. I dont know how to filtered multiple fields.
            if(filtered.count == 0 || countElements(searchBar.text) == 0)
            {
                searchActive = false
                self.countryTableView.reloadData()
            }
            else
            {
                searchActive = true
                self.countryTableView.reloadData()
            }

        }
        else
        {

            searchActive = false
            self.countryTableView.reloadData()
        }

    }

func tableView(tableView: UITableView, cellForRowAtIndexPath indexPath: NSIndexPath) -> UITableViewCell {
        let cell = countryTableView.dequeueReusableCellWithIdentifier("country", forIndexPath: indexPath) as country_tblCell

        //println("Cell for ROws \(searchActive)")
        if(searchActive)
        {
            if(filtered.count == 0 || countElements(searchBar.text) == 0)
            {
                searchActive = false
                self.countryTableView.reloadData()
            }

            else
            {
                println("First Index \(indexPath.row)")
                cell.country_Label.text = filtered[indexPath.row]
                cell.countryCodeLabel.text = countryCodes[indexPath.row] //Here need to display filtered datas for Country code.
                println("Second Index \(indexPath.row)")
            }
        }
        else
        {
            println("Normal First Index \(indexPath.row)")
            cell.selectionStyle = .None
            cell.country_Label.text = countries[indexPath.row]
            cell.countryCodeLabel.text = countryCodes[indexPath.row]
            cell.layer.borderColor = validateBorderColor.CGColor
            cell.layer.borderWidth = 1
            println("Normal Second Index \(indexPath.row)")
        }

        return cell
    }

我的输出

尝试使用元组

这是swift中的一个重要功能

获取

国家/地区

和

国家/地区代码

将它们添加到此元组

var countryAndCode: [(country:String , code: String)] = []
for i in 0...coutries.count {
  countryAndCode.append(country:countries[i] , code:country_codes[i])//this shows error in XCode some times
    //if the above code doesn't compile then use the below code
  countryAndCode += [(country:countries[i] , code:country_codes[i])]
}

cell.country_Label.text = filtered[indexPath.row].country
cell.countryCodeLabel.text = filtered[indexPath.row].code

然后在此元组上执行筛选：

filtered = countryAndCode.filter({ (data) -> Bool in
        let tmp: NSString = data.country // the name from the variable decleration
            let range = tmp.rangeOfString(searchText, options: NSStringCompareOptions.CaseInsensitiveSearch)
            return range.location != NSNotFound
        })

filtered = countryAndCode.filter({ (data) -> Bool in
     let tmp: NSString = data.country // the name from the variable decleration
     let range = tmp.range(of: searchText, options: .caseInsensitive)
     return range.location != NSNotFound
})

最后，在

cellforrowatinexpath

方法中使用此元组

var countryAndCode: [(country:String , code: String)] = []
for i in 0...coutries.count {
  countryAndCode.append(country:countries[i] , code:country_codes[i])//this shows error in XCode some times
    //if the above code doesn't compile then use the below code
  countryAndCode += [(country:countries[i] , code:country_codes[i])]
}

cell.country_Label.text = filtered[indexPath.row].country
cell.countryCodeLabel.text = filtered[indexPath.row].code

---

有关元组的更多信息，请访问

我之前遇到过类似的问题。我想第一步也是一样的。创建一个元组，其中国家和代码位于一个对象中

var countryAndCode: [(country:String , code: String)] = []

然后我基本上对字段使用OR运算符。您的代码：

        filtered = countries.filter({ (text) -> Bool in
            let tmp: NSString = text.attribute
            let range = tmp.rangeOfString(searchText, options: NSStringCompareOptions.CaseInsensitiveSearch)
            return range.location != NSNotFound
        })

变成这样：

        filtered = countries.filter({ (text) -> Bool in
            let tmp: NSString = text.attribute
            let range = tmp.country.rangeOfString(searchText, options: NSStringCompareOptions.CaseInsensitiveSearch) || tmp.code.rangeOfString(searchText, options: NSStringCompareOptions.CaseInsensitiveSearch)
            return range.location != NSNotFound
        })

---

在您的情况下，如果您想在这两个字段上进行筛选，您可以执行&&操作。

以上以Swift 3.0回答

var countryAndCode: [(country:String , code: String)] = []
for i in 0...coutries.count-1 {
  countryAndCode += [(country:countries[i] , code:country_codes[i])]
}

然后在此元组上执行筛选：

filtered = countryAndCode.filter({ (data) -> Bool in
        let tmp: NSString = data.country // the name from the variable decleration
            let range = tmp.rangeOfString(searchText, options: NSStringCompareOptions.CaseInsensitiveSearch)
            return range.location != NSNotFound
        })

filtered = countryAndCode.filter({ (data) -> Bool in
     let tmp: NSString = data.country // the name from the variable decleration
     let range = tmp.range(of: searchText, options: .caseInsensitive)
     return range.location != NSNotFound
})

---

谢谢@Raja。让tmp:NSString=data.country。我听不懂这一行？我问的是“data.country”“filtered=countryAndCode.filter”，这一行我有一个错误。（国家/地区：字符串，代码：字符串）与不相同String@McDonal_11对象名称

国家/地区

。因此，将来要引用元组中的country部分，我们将其命名为：

countryAndCode[1]。country

。在这里，当使用

.filter

方法进行过滤时，我们获取数组的每个对象，它是一个元组，并将其分配给

数据

。因此，要访问元组的

country

部分，我们使用

data.country

yes@Raja！！我明白了。“filtered=countryAndCode.filter”，，在这一行我得到了一个错误。（国家/地区：字符串，代码：字符串）与字符串不相同。我不知道是什么原因导致了这个错误？在不指定属性的情况下，如何使用let tmp:NSString=text？如果我不使用text.attributeName，我会出错。我无法将类型为“（进程：String，请求者：String，创建：String，状态：String）”的值转换为指定的类型“NSString”，因此countries数组中的对象是字符串，但clojure需要NSString，并且显然无法转换。已经有一段时间了。看看这个问题和答案：