swift:与‘不相同;UIPickerView’;
我尝试了以下在Obj-C中有效的方法,但在swift中出错: “(@lvalue UIPickerView!,titleForRow:Int,forComponent:Int)->$T7”与“UIPickerView”不同swift:与‘不相同;UIPickerView’;,swift,uipickerview,Swift,Uipickerview,我尝试了以下在Obj-C中有效的方法,但在swift中出错: “(@lvalue UIPickerView!,titleForRow:Int,forComponent:Int)->$T7”与“UIPickerView”不同 func pickerView(pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusingView view: UIView!) -> UIView
func pickerView(pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusingView view: UIView!) -> UIView
{
var pickerLabel = UILabel()
pickerLabel.textColor = UIColor.whiteColor()
pickerLabel.text = pickerView(pickerView, titleForRow: row, forComponent: component)
return pickerLabel
}
以下是obj-c工作代码:
- (UIView *)pickerView:(UIPickerView *)pickerView viewForRow:(NSInteger)row forComponent:(NSInteger)component reusingView:(UIView *)view{
UILabel* pickerLabel = (UILabel*)view;
if (!pickerLabel){
pickerLabel = [[UILabel alloc] init];
[pickerLabel setFont:[UIFont fontWithName:@"Helvetica Neue Bold Italic" size:25]];
}
pickerLabel.textAlignment = NSTextAlignmentCenter;
pickerLabel.textColor = [UIColor whiteColor];
pickerLabel.text=[self pickerView:pickerView titleForRow:row forComponent:component];
return pickerLabel;
}
- (NSString *)pickerView:(UIPickerView *)pickerView titleForRow:(NSInteger)row forComponent:(NSInteger)component {
if (component == 0){
if ([unitType isEqualToString:@"MS"]) {
return [thickness objectAtIndex:row];
}else{
NSString *th = [thickness objectAtIndex:row];
float tt = [th floatValue]*0.039370078740157;
NSString *new_th = [NSString stringWithFormat:@"%2.2f",tt];
return new_th;
}
}
if(component ==1){
if ([unitType isEqualToString:@"MS"]) {
return [weight_data objectAtIndex:row];
}else{
NSString *wei = [weight_data objectAtIndex:row];
float ww = [wei floatValue]*2.205;
NSString *new_wei = [NSString stringWithFormat:@"%3.1f",ww];
return new_wei;
}
}
我认为您想打印从
UIPickerView
中选择索引的数据,但我认为您这样做是错误的
以下是两个示例:
var states : [String]!
func pickerView(pickerView: UIPickerView, viewForRow row: Int,
forComponent component: Int, reusingView view: UIView!) -> UIView {
var lab : UILabel
if let label = view as? UILabel {
lab = label
println("reusing label")
} else {
lab = MyLabel()
println("making new label")
}
// You can set text this way where states is an array of string.
lab.text = self.states[row]
lab.backgroundColor = UIColor.clearColor()
lab.sizeToFit()
return lab
}
}
引自
另一个例子是:
func pickerView(pickerView: UIPickerView, viewForRow row: Int, forComponent component: Int, reusingView view: UIView!) -> UIView {
var pickerLabel = view as UILabel!
if view == nil { //if no label there yet
pickerLabel = UILabel()
//color the label's background
let hue = CGFloat(row)/CGFloat(pickerData.count)
pickerLabel.backgroundColor = UIColor(hue: hue, saturation: 1.0, brightness: 1.0, alpha: 1.0)
}
let titleData = pickerData[row]
let myTitle = NSAttributedString(string: titleData, attributes: [NSFontAttributeName:UIFont(name: "Georgia", size: 26.0)!,NSForegroundColorAttributeName:UIColor.blackColor()])
//This way you can set text for your label.
pickerLabel!.attributedText = myTitle
return pickerLabel
}
引用自
希望这对您有所帮助。有3个参数的pickerView()方法的返回时间是多少请显示完整代码..pickerLabel.text=[self-pickerView:pickerView titleForRow:row forComponent:component];显示完整的代码。使用上面的方法再次获取正确的数据,因为数据可能需要再次计算。显示创建标题的方法的整个Swift实现。
pickerView(\uU:titleForRow:forComponent:)
pickerView(\uU:attributedTitleForRow:forComponent:)
pickerView(\uU:viewForRow:forComponent:reusingView:)上面三个也可以显示pickerview内容,但不应该同时使用它们,我不知怎么用了其中两个。现在只使用最后一个,问题就解决了。谢谢大家。顺便说一句,它确实适用于obj-c,所以我认为swift可以。我需要使用[self-pickerView:pickerView titleForRow:row forComponent:component]重新获得重新计算的标题数据,并按照您提供的引用找到原因。谢谢。