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Swift [NSObject:AnyObject]!和接缝隔离装置_Swift_Facebook Sdk 4.0 - Fatal编程技术网

Swift [NSObject:AnyObject]!和接缝隔离装置

Swift [NSObject:AnyObject]!和接缝隔离装置,swift,facebook-sdk-4.0,Swift,Facebook Sdk 4.0,如何从以下函数的结果(字典)中获取字符串值(joinWithSeparator) func gameRequestDialog(gameRequestDialog: FBSDKGameRequestDialog!, didCompleteWithResults results: [NSObject : AnyObject]!){ NSLog("resoult.count: %i", results.count) let res = results["to"] //

如何从以下函数的结果(字典)中获取字符串值(joinWithSeparator)

func gameRequestDialog(gameRequestDialog: FBSDKGameRequestDialog!, didCompleteWithResults results: [NSObject : AnyObject]!){
        NSLog("resoult.count: %i", results.count)
        let res = results["to"] // This is a Key Value par
        let res = results["to"] as Dictionary // Error: has no subscript members
        let res = results?["to"] as Dictionary // Error: Value of optional type 'AnyObject' not unwrapped.


...
结果包括:

([NSObject : AnyObject]!) results = 5 key/value pairs {
  [0] = {
    key = 0x000
    value = 0x000
  }
  [1] = {
    key = 0x000
    value = 0x000
  }
  [2] = {
    key = 0x000
    value = 0x000
  }
  [3] = {
    key = 0x000
    value = 0x000
  }
  [4] = {
    key = 0x000
    value = 0x000
  }
}
我在寻找类似于
res.joinWithSeparator(“,”)
的东西来获取一个包含值的字符串


提前感谢

我将对Dictionary进行扩展,以获得包含所有值的字符串

大概是这样的:

extension Dictionary {
    var joinedValues:String {
        return self.values.map { String($0) }.joinWithSeparator(", ")
    }
}
用法示例:

let dict = ["name":"Mike", "age":42, "gender":"male"]

let valuesAsString = dict.joinedValues  // "male, 42, Mike"

当然,只有当您的值可以通过String()转换为字符串时,它才会起作用。如果没有,则必须根据值的类型进行特定扩展。

能否举例说明结果字典的外观?可能是一些数据,因为我们可以看到它是
[NSObject:AnyObject]
。您希望输出是什么?可能是一个包含字典所有值的字符串?或者甚至是一个包含键和值的字符串?