Swift NSOpenPanel as板材

我环顾了一下其他的答案，但似乎没有什么对我的情况有帮助

我有一个viewController类，它包含一个按钮的iAction。此按钮应将NSOpenPanel作为图纸从该viewController打开：

class ViewController: NSViewController {
@IBAction func folderSelection(sender: AnyObject) {
    var myFiledialog: NSOpenPanel = NSOpenPanel()
    myFiledialog.prompt = "Select path"
    myFiledialog.worksWhenModal = true
    myFiledialog.allowsMultipleSelection = false
    myFiledialog.canChooseDirectories = true
    myFiledialog.canChooseFiles = false
    myFiledialog.resolvesAliases = true

    //myFiledialog.runModal()

    myFiledialog.beginSheetModalForWindow(self.view.window!, completionHandler: nil)


    var chosenpath = myFiledialog.URL
    if (chosenpath!= nil)
    {
        var TheFile = chosenpath!.absoluteString!
        println(TheFile)
        //do something with TheFile
    }
    else
    {
        println("nothing chosen")
    }
}
}

---

问题来自myFileDialog.beginSheetModalForWindow（..），它与上面的行一起工作，但这不是图纸效果

您需要从窗口上的面板调用

beginSheetModalForWindow

，并使用完成块：

let myFiledialog = NSOpenPanel()
myFiledialog.prompt = "Select path"
myFiledialog.worksWhenModal = true
myFiledialog.allowsMultipleSelection = false
myFiledialog.canChooseDirectories = true
myFiledialog.canChooseFiles = false
myFiledialog.resolvesAliases = true
myFiledialog.beginSheetModalForWindow(window, completionHandler: { num in
    if num == NSModalResponseOK {
        let path = myFiledialog.URL
        print(path)
    } else {
        print("nothing chosen")
    }
})

---

Swift 5

let dialog=NSOpenPanel（）
dialog.beginSheetModal（用于：self.view.window！）{结果
如果result=.OK，则让url=dialog.url{
打印（“获取”，url）
}
}