Syntax 使用多个条件过滤对象,包括比较两个对象字段
有一个JSON对象的列表,我试图根据最小值检查和它的两个字段之间的比较来过滤它们Syntax 使用多个条件过滤对象,包括比较两个对象字段,syntax,jq,Syntax,Jq,有一个JSON对象的列表,我试图根据最小值检查和它的两个字段之间的比较来过滤它们 { "preview": false, "init_offset": 0, "messages": [], "fields": [ { "name": "A" }, { "name": "B" }, { "name": "Diff" }, { "name": "Threshold" }
{
"preview": false,
"init_offset": 0,
"messages": [],
"fields": [
{
"name": "A"
},
{
"name": "B"
},
{
"name": "Diff"
},
{
"name": "Threshold"
}
],
"results": [
{
"A": "foo",
"B": "bar",
"Diff": "1095",
"Threshold": "1200"
},
{
"A": "baz",
"B": "bux",
"Diff": "81793",
"Threshold": "0"
},
{
"A": "quux",
"B": "quuz",
"Diff": "194"
},
{
"A": "moo",
"B": "goo",
"Diff": "5000",
"Threshold": "2000"
}
]
}
我最接近的是
.results
| map(.Threshold //= "0")
| .[]
| select((.Threshold|tonumber > 0) and
(.Diff|tonumber > .Threshold|tonumber))
但这给了我们一个机会
Cannot index string with string "Threshold"
错误
基本上,我想返回Diff大于非零阈值的所有结果。因此,在这种情况下:
{
"A": "moo",
"B": "goo",
"Diff": "5000",
"Threshold": "2000"
}
使用jq1.5fwiw.您只是缺少一些括号。比较:
select((.Threshold|tonumber) > 0 and
(.Diff|tonumber) > (.Threshold|tonumber))
或者避免双重转换:
select( (.Threshold|tonumber) as $t
| $t > 0 and (.Diff|tonumber) > $t )
您还可以稍微简化整个程序:
.results[]
| select( ((.Threshold // 0) | tonumber) as $t
| $t > 0 and (.Diff|tonumber) > $t )
给出
jq:error(在jq1:44):null(null)不能被解析为数字。需要jq.results[]|为没有Threshold的对象选择(.Threshold和(.Threshold|tonumber)作为$t |$t>0和((.Diff|tonumber)>$t))
key@RomanPerekrest-我只是显示“选择”行,而不是完整的程序。另外,您的备选方案也会更改语义。