Tsql XML表达式的嵌套

我尝试了一个类似于“FOR XML表达式嵌套”的FOR XML查询。我的问题是我必须有三个XML元素级别。结果应该是这样的

<StepTree Name="ALFKI">
  <Step Name="Foo">
    <Result id="123" />
    <Result id="456" />
  </Step>
  <Step Name="Bar">
    <Result id="789" />
    <Result id="987" />
  </Step>
</StepTree >

生成的XML如下所示

<StepTree Name="ALFKI">
  <Step Name="Foo" />
  <Step Name="Bar">
    <Result id="123" />
    <Result id="456" />
    <Result id="789" />
    <Result id="987" />
  </Step>
</StepTree >

有什么想法吗？

使用此查询：

SELECT 1 as TAG,
   NULL as Parent,
   StepTrees.Name AS [StepTree!1!Name],
   NULL as [Step!2!Name],
   NULL as [Result!3!id]
FROM StepTrees
WHERE StepTrees.Name = 'ALFKI' 
UNION ALL
SELECT 2,
       1,
       Null,
       Steps.Name,
       NULL
FROM Steps
JOIN StepTrees ON Steps.StepTreeId = StepTrees.Id
WHERE StepTrees.Name = 'ALFKI' 
UNION ALL
SELECT DISTINCT 3,
       2,
       Null,
       Steps.Name,
       Results.id
FROM StepTrees
JOIN Steps ON Steps.StepTreeId = StepTrees.Id
JOIN Results ON Steps.StepId = Results.StepId
ORDER BY [Step!2!Name],[Result!3!id]
FOR XML EXPLICIT

---

是的，只要我在最后一个SELECT中添加相同的WHERE子句，就可以了。不知道ORBER对XML形状的影响。非常感谢你卢比奥

SELECT 1 as TAG,
   NULL as Parent,
   StepTrees.Name AS [StepTree!1!Name],
   NULL as [Step!2!Name],
   NULL as [Result!3!id]
FROM StepTrees
WHERE StepTrees.Name = 'ALFKI' 
UNION ALL
SELECT 2,
       1,
       Null,
       Steps.Name,
       NULL
FROM Steps
JOIN StepTrees ON Steps.StepTreeId = StepTrees.Id
WHERE StepTrees.Name = 'ALFKI' 
UNION ALL
SELECT DISTINCT 3,
       2,
       Null,
       Steps.Name,
       Results.id
FROM StepTrees
JOIN Steps ON Steps.StepTreeId = StepTrees.Id
JOIN Results ON Steps.StepId = Results.StepId
ORDER BY [Step!2!Name],[Result!3!id]
FOR XML EXPLICIT