Unity3d 时间分数乘数_Unity3d_Time_Multiplication_Unity5_Seconds

Unity3d 时间分数乘数

unity3d time

Unity3d 时间分数乘数,unity3d,time,multiplication,unity5,seconds,Unity3d,Time,Multiplication,Unity5,Seconds,这是我制作的分数管理器脚本： using UnityEngine; using System.Collections; using UnityEngine.UI; public class ScoreManager : MonoBehaviour { public Text scoreText; public float scoreCount; // What the score is when the scene first loads. I set this

这是我制作的分数管理器脚本：

using UnityEngine;
 using System.Collections;
 using UnityEngine.UI;

 public class ScoreManager : MonoBehaviour {

     public Text scoreText;

     public float scoreCount; // What the score is when the scene first loads. I set this as zero.

     public float pointsPerSecond; // Every second, the points increase by THIS amount. Right now it is 100.

     // Update is called once per frame
     void Update () {

         scoreCount += pointsPerSecond * Time.deltaTime;

         scoreText.text = "" + Mathf.Round (scoreCount); // It comes out as a float with like 6 decimals; I round to an nice, clean Integer 

     }
 }

我无法解决的问题是：如何制作一个乘数，在30秒后将分数乘以2，然后在1分钟后将分数乘以3，然后在1分30秒后乘以4，最后在2分钟后乘以5？谢谢：）

这是使用

IEnmurator

功能的绝佳机会。这些是您可以调用的方法，您可以告诉它们在恢复之前等待一段时间。所以在你的例子中，你可以有一个

IEnumerator

函数，每30秒乘以你的分数。例如：

public Text scoreText;

public float scoreCount; // What the score is when the scene first loads. I set this as zero.

public float pointsPerSecond; // Every second, the points increase by THIS amount. Right now it is 100.

private int scoreMultiplier = 1;

void Start()
{
    StartCoroutine(MultiplyScore());
}

// Update is called once per frame
 void Update () 
{

     scoreCount += pointsPerSecond * Time.deltaTime;

     scoreText.text = "" + Mathf.Round (scoreCount); // It comes out as a float with like 6 decimals; I round to an nice, clean Integer 

 }

IEnumerator MultiplyScore()
{
    while(true)
    {
        yield return new WaitForSeconds(30);
        scoreMultiplier++;
        scoreCount *= scoreMultiplier;
    }
}

注意，如果您只想将乘法增加到5倍，则可以使用score乘数变量作为

IEnumerator

中的条件，同时循环如下：

IEnumerator MultiplyScore()
{
    while(scoreMultiplier < 5)
    {
        yield return new WaitForSeconds(30);
        scoreMultiplier++;
        scoreCount *= scoreMultiplier;
    }
}

IEnumerator multilyscore（）
{
而（分数乘数<5）
{
返回新的等待秒（30）；
分数乘法器++；
scoreCount*=分数乘数；
}
}