使用SurfaceListBox的WPF-高亮显示颜色选择

使用SurfaceListBox的WPF-高亮显示颜色选择,wpf,listbox,transparent,Wpf,Listbox,Transparent,我需要帮助来更改SurfaceListBox选择的颜色 目前,我使用的是: <Style x:Key="styleSurfaceListBox" TargetType="{x:Type my:SurfaceListBox}"> <Setter Property="ItemsPanel"> <Setter.Value> <ItemsPanelTemplate> <Stac

我需要帮助来更改SurfaceListBox选择的颜色

目前,我使用的是:

<Style x:Key="styleSurfaceListBox" TargetType="{x:Type my:SurfaceListBox}">
    <Setter Property="ItemsPanel">
       <Setter.Value>
           <ItemsPanelTemplate>
               <StackPanel Orientation="Horizontal"
               VerticalAlignment="Center"
               HorizontalAlignment="Center"
               Background="Transparent" />                        
           </ItemsPanelTemplate>
        </Setter.Value>
    </Setter>            
</Style>

我需要什么使选择的颜色透明?

多亏了dvvrd

我创建我的
SurfaceListBoxItem
样式如下:

     <Style x:Key="item" TargetType="{x:Type my:SurfaceListBoxItem}"  >
        <Style.Triggers>
            <Trigger Property="IsSelected" Value="true">
                <Setter Property="Foreground" Value="Transparent" />
                <Setter Property="Background" Value="Transparent" />
            </Trigger>
            <Trigger Property="IsFocused" Value="true">
                <Setter Property="Foreground" Value="Transparent" />
                <Setter Property="Background" Value="Transparent" />
            </Trigger>

            <Trigger Property="IsEnabled" Value="true">
                <Setter Property="Foreground" Value="Transparent" />
                <Setter Property="Background" Value="Transparent" />
            </Trigger>
            <Trigger Property="IsMouseOver" Value="true">
                <Setter Property="Foreground" Value="Transparent" />
                <Setter Property="Background" Value="Transparent" />
            </Trigger>                
        </Style.Triggers>
    </Style>

再次感谢dvvrd

你可以找到答案,非常感谢!!!太完美了!!!
SurfaceListBox1.ItemContainerStyle = (Style)this.Resources["item"]; //item is the KEY on my style.