Xcode 如何从scrollview中的imageview中获取标签号?
从imageview获取标签号时遇到问题。 我向scrollview中的每个ImageView添加了UIgestureRecognitor,并尝试从触摸视图中获取标签号。 在我触摸图像后,什么也没有发生。 我的代码错了吗?请帮帮我Xcode 如何从scrollview中的imageview中获取标签号?,xcode,tags,touch,imageview,scrollview,Xcode,Tags,Touch,Imageview,Scrollview,从imageview获取标签号时遇到问题。 我向scrollview中的每个ImageView添加了UIgestureRecognitor,并尝试从触摸视图中获取标签号。 在我触摸图像后,什么也没有发生。 我的代码错了吗?请帮帮我 // to add images for (int i = 0; i < app.arrPhotoList.count; i++) { UIImageView *subImg = [[UIImageView alloc]init
// to add images
for (int i = 0; i < app.arrPhotoList.count; i++) {
UIImageView *subImg = [[UIImageView alloc]initWithFrame:frame];
subImg.contentMode = UIViewContentModeScaleAspectFit;
subImg.layer.borderColor = [UIColor blackColor].CGColor;
subImg.layer.borderWidth = 2.0f;
subImg.tag = i;
subImg.userInteractionEnabled = YES;
UIGestureRecognizer *singleTab = [[UIGestureRecognizer alloc]initWithTarget:self action:@selector(imageTag:)];
[subImg addGestureRecognizer:singleTab];
/////// add img to array of imageviews/////////////
NSString *imgName = [[app.arrPhotoList objectAtIndex:i]stringByAppendingString:@"_thumb.jpg"];
subImg.image = [UIImage imageWithContentsOfFile:imgName];
[scrImgView addSubview:subImg];
}
-(void) imageTag:(UIGestureRecognizer *)sender{
NSLog(@"you selected tag number is : %d",sender.view.tag);
}
换行
UIGestureRecognizer *singleTab = [[UIGestureRecognizer alloc]initWithTarget:self action:@selector(imageTag:)];
对此
UITapGestureRecognizer *singleTab = [[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(imageTag:)];
HTH.更改此行
UIGestureRecognizer *singleTab = [[UIGestureRecognizer alloc]initWithTarget:self action:@selector(imageTag:)];
对此
UITapGestureRecognizer *singleTab = [[UITapGestureRecognizer alloc]initWithTarget:self action:@selector(imageTag:)];
HTH.您应该编写UITapGestureRecognizer而不是UIGestureRecognizer,并设置委托。如需了解更多信息,请参阅
我认为这将对您有所帮助。您应该编写UICapgestureRecognizer而不是UIGestureRecognizer,并设置委派。如需了解更多信息,请参阅
我想这会对你有所帮助。顺便说一句,我在singleTap.delegate=self上收到了警告消息;这是“将*const_strong传递给不兼容类型“id”的参数,我认为这是因为委托类型是UIgestureRecognitor。有没有办法解决这个警告消息?你必须在class.h文件中添加uigestureRecognitizerDelegate,比如@interface yourClass:uiviewcontroller再次感谢你!今天我从你那里得到了很多东西;顺便说一下,我在singleTap.delegate=self上收到了警告消息;这是“将*const_strong传递给不兼容类型“id”的参数,我认为这是因为委托类型是UIgestureRecognitor。有没有办法解决这个警告消息?你必须在class.h文件中添加uigestureRecognitizerDelegate,比如@interface yourClass:uiviewcontroller再次感谢你!今天我从你那里得到了很多东西;