加载xml";“行”;进入R数据表
我有一些数据是这样的:加载xml";“行”;进入R数据表,xml,r,dataframe,Xml,R,Dataframe,我有一些数据是这样的: <people> <person first="Mary" last="Jane" sex="F" /> <person first="Susan" last="Smith" sex="F" height="168" /> <person last="Black" first="Joseph" sex="M" /> <person first="Jessica" last="Jones" sex="F"
<people>
<person first="Mary" last="Jane" sex="F" />
<person first="Susan" last="Smith" sex="F" height="168" />
<person last="Black" first="Joseph" sex="M" />
<person first="Jessica" last="Jones" sex="F" />
</people>
first last sex height
1 Mary Jane F NA
2 Susan Smith F 168
3 Joseph Black M NA
4 Jessica Jones F NA
我已经走了这么远:
library(XML)
xpeople <- xmlRoot(xmlParse(xml))
lst <- xmlApply(xpeople, xmlAttrs)
names(lst) <- 1:length(lst)
库(XML)
xpeopletxtplyr::rbind.fill(lappy(xmlToList(txt),函数(x)as.data.frame(t(x),stringsAsFactors=FALSE))
可能稍微容易一点,但不是xml解决方案。然后,您可以使用as.numeric(
实际上可能有用)将因子高度转换为数值。有一个函数可以将属性获取到data.frameXML:::xmlatrstodataframe(XML[“//person”])
lst <- xmlApply(xpeople, function(node) {
attrs = xmlAttrs(node)
if (!("height" %in% names(attrs))) {
attrs[["height"]] <- NA
}
attrs
})
df = as.data.frame(lst)
txt <- '<people>
<person first="Mary" last="Jane" sex="F" />
<person first="Susan" last="Smith" sex="F" height="168" />
<person last="Black" first="Joseph" sex="M" />
<person first="Jessica" last="Jones" sex="F" />
</people>'
library(XML) # for xmlTreeParse
library(data.table) # for rbindlist(...)
xml <- xmlTreeParse(txt, asText=TRUE, useInternalNodes = TRUE)
rbindlist(lapply(xml["//person"],function(x)as.list(xmlAttrs(x))),fill=TRUE)
# first last sex height
# 1: Mary Jane F NA
# 2: Susan Smith F 168
# 3: Joseph Black M NA
# 4: Jessica Jones F NA