Warning: file_get_contents(/data/phpspider/zhask/data//catemap/0/xml/14.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
Xml 在VB.NET中读取childelement到XElement_Xml_Vb.net_Xelement - Fatal编程技术网

Xml 在VB.NET中读取childelement到XElement

Xml 在VB.NET中读取childelement到XElement,xml,vb.net,xelement,Xml,Vb.net,Xelement,我一直在尝试使用VB.NET读取XML文件,经过2-3个小时的谷歌搜索和阅读后,我朝着正确的方向前进,但是现在我停了下来,找不到任何对我有意义的答案 这是我拥有的XML: <?xml version="1.0" encoding="ISO-8859-1"?> <exportCustomerInformation xmlns="http://www.testdom.se/server/services/exportCustomerInformationNavision" xmln

我一直在尝试使用VB.NET读取XML文件,经过2-3个小时的谷歌搜索和阅读后,我朝着正确的方向前进,但是现在我停了下来,找不到任何对我有意义的答案

这是我拥有的XML:

<?xml version="1.0" encoding="ISO-8859-1"?>
<exportCustomerInformation xmlns="http://www.testdom.se/server/services/exportCustomerInformationNavision" xmlns:met="http://www.testdom.se/server/services/metadata" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
    <data>
        <customers>
            <customerInformation xmlns:nav="http://www.testdom.se/server/services/integration/navision">
                <nav:littera/>
                <nav:parentUuid/>
                <nav:name>TESTBEDRIFTEN AS</nav:name>
                <nav:uuid>77cf992e-766a-4496-9a5a-5105a75214ce</nav:uuid>
                <nav:customerType>1</nav:customerType>
                <nav:emailAddress/>
                <nav:industryBranch/>
                <nav:department>TRONDHEIM</nav:department>
                <nav:invoicingAddress>
                    <nav:streetName>PO BOX 123</nav:streetName>
                    <nav:streetNumber/>
                    <nav:recipient/>
                    <nav:postalCode>7407</nav:postalCode>
                    <nav:city>TRONDHEIM</nav:city>
                    <nav:country>NORWAY</nav:country>
                </nav:invoicingAddress>
                <nav:deliveryAddress>
                    <nav:placeName>TESTBEDRIFTEN AS</nav:placeName>
                <nav:streetName>STORGATEN</nav:streetName>
                    <nav:streetNumber>1</nav:streetNumber>
                    <nav:recipient/>
                    <nav:postalCode>7011</nav:postalCode>
                    <nav:city>TRONDHEIM</nav:city>
                    <nav:country>NORWAY</nav:country>
                </nav:deliveryAddress>
            </customerInformation>
        </customers>
    </data>
</exportCustomerInformation>
为了阅读本文,我有以下代码:

Dim xmlDoc = XDocument.Load(file)
    For Each dataXML As XElement In xmlDoc...<customerInformation>

        oDR = oDT.NewRow
        oDR("parentUuid") = dataXML...<nav:parentUuid>.Value
        oDR("name") = dataXML...<nav:name>.Value
        oDR("uuid") = dataXML...<nav:uuid>.Value
        oDR("customerType") = dataXML...<nav:customerType>.Value
        oDR("emailAddress") = dataXML...<nav:emailAddress>.Value

        'What to here in order to get to these children?
        oDR("invStreetName") = dataXML.<nav:invoicingAddress>.<nav:invStreetName>.Value
        oDR("invStreetNumber") = dataXML.<nav:invoicingAddress>...<nav:invStreetNumber>.Value
        oDR("invName") = dataXML.<nav:invoicingAddress>...<nav:invName>.Value
        oDR("invPostalCode") = dataXML.<nav:invoicingAddress>...<nav:invPostalCode>.Value
        oDR("invCity") = dataXML.<nav:invoicingAddress>...<nav:invCity>.Value
        oDR("invCountry") = dataXML.<nav:invoicingAddress>...<nav:invCountry>.Value

    Next
所以,我的问题是。如何访问节点下的子节点

我上面提供的代码没有多大用处:P

非常感谢您的帮助


//Jaggen

假设doc包含XDocument,下面是一个丑陋的示例:

Dim customerInfo = doc.Root.Elements.First.Elements.First.Elements.First

Dim invoicingAddress = _
customerInfo.Elements.First(Function(x) x.Name.LocalName = "invoicingAddress")

Dim streetName = _
invoicingAddress.Elements.First(Function(x) x.Name.LocalName = "streetName").Value

我想我明白了。可能不是最优雅的解决方案,但在这种特殊情况下,效果很好oDRdelPlaceName=dataXML….subjects.ElementAt0.Value子代。ElementAt[n]造成了所有的差异://JaggenThanks。很有魅力