Xml Perl foreach循环dilema
我正在循环遍历XML节点,并为每个相似的节点创建一个组,例如以下节点:Xml Perl foreach循环dilema,xml,perl,loops,foreach,Xml,Perl,Loops,Foreach,我正在循环遍历XML节点,并为每个相似的节点创建一个组,例如以下节点: <node name="ps1_uat1" host="" port="20014" /> <node name="ps1_uat2" host="" port="20014" /> <node name="ps1_uat3" host="" port="20014" /> 非常感谢您的帮助。我相信您需要将两行代码移出内部for循环。试试这个: foreach my $group (@g
<node name="ps1_uat1" host="" port="20014" />
<node name="ps1_uat2" host="" port="20014" />
<node name="ps1_uat3" host="" port="20014" />
非常感谢您的帮助。我相信您需要将两行代码移出内部for循环。试试这个:
foreach my $group (@groups) {
my @nodes;
foreach my $node (@nodenames) {
chomp($group);
chomp($node);
if ($node =~ m/$group/) {
push (@nodes, "$node,");
}
}
// These 2 lines go out
my $groupxml = "\t<nodeGroup name=\"$group\" nodes=\"@nodes\" \/>\n";
print ODSERVERFILE $groupxml;
}
}
foreach my$group(@groups){
我的@nodes;
foreach my$node(@nodenames){
chomp($组);
chomp($node);
如果($node=~m/$group/){
推送(@nodes,“$node”);
}
}
//这两条线断了
my$groupxml=“\t\n”;
打印ODSERVERFILE$groupxml;
}
}
就是这样。这么简单,却错过了。非常感谢你。
<nodeGroup name="ps1" nodes="ps1_it," />
<nodeGroup name="ps1" nodes="ps1_it, ps1_uat1," />
<nodeGroup name="ps1" nodes="ps1_it, ps1_uat1, ps1_uat2," />
<nodeGroup name="ps1" nodes="ps1_it, ps1_uat1, ps1_uat2, ps1_uat3," />
foreach my $group (@groups) {
my @nodes;
foreach my $node (@nodenames) {
chomp($group);
chomp($node);
if ($node =~ m/$group/) {
push (@nodes, "$node,");
my $groupxml = "\t<nodeGroup name=\"$group\" nodes=\"@nodes\" \/>\n";
print ODSERVERFILE $groupxml;
}
}
}
foreach my $group (@groups) {
my @nodes;
foreach my $node (@nodenames) {
chomp($group);
chomp($node);
if ($node =~ m/$group/) {
push (@nodes, "$node,");
}
}
// These 2 lines go out
my $groupxml = "\t<nodeGroup name=\"$group\" nodes=\"@nodes\" \/>\n";
print ODSERVERFILE $groupxml;
}
}