Can'；t编写xpath表达式以访问图像链接

一堂空白课把我的表情搞乱了。以下是图像链接的html元素：

<div data-index="0" style="width: 300px; left: 0px; transition-duration: 0ms; transform: translate(0px, 0px);"><img alt="" class="" src="https://images.craigslist.org/00G0G_40m7DOu6DO3_300x300.jpg"></div>

---

//div/img[@class='abc']/@src

尝试为类命名并使用[27]：text=“””中的xpath表达式

In [27]: text = """ <div data-index="0" style="width: 300px; left: 0px; transiti
...: on-duration: 0ms; transform: translate(0px, 0px);"><img alt="" class=""
...:  src="https://images.craigslist.org/00G0G_40m7DOu6DO3_300x300.jpg"></di
...: v>"""

In [28]: from scrapy.selector import Selector
In [29]: sel = Selector(text=text)
In [30]: sel.xpath('//img[@class=""]/@src').extract()
Out[31]: ['https://images.craigslist.org/00G0G_40m7DOu6DO3_300x300.jpg']

在[28]中：从scrapy.selector导入选择器 在[29]中：sel=选择器（文本=文本） [30]中的sel.xpath（'//img[@class=”“]/@src'）.extract（） Out[31]：['https://images.craigslist.org/00G0G_40m7DOu6DO3_300x300.jpg']

---

XPath看起来不错。这个错误并不是你想象的那样。谢谢托马拉克先生的回答。不知道如何找到图像链接。感谢Vikram Saini的回复。但是，还是和我申请的一样。那么你可以试试//div/img[@src]

In [27]: text = """ <div data-index="0" style="width: 300px; left: 0px; transiti
...: on-duration: 0ms; transform: translate(0px, 0px);"><img alt="" class=""
...:  src="https://images.craigslist.org/00G0G_40m7DOu6DO3_300x300.jpg"></di
...: v>"""

In [28]: from scrapy.selector import Selector
In [29]: sel = Selector(text=text)
In [30]: sel.xpath('//img[@class=""]/@src').extract()
Out[31]: ['https://images.craigslist.org/00G0G_40m7DOu6DO3_300x300.jpg']